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Nata [24]
3 years ago
9

Plz help me plzz i beg of u

Mathematics
1 answer:
Stells [14]3 years ago
7 0

Answer:

2.0 x 10^11

Step-by-step explanation:

2.6 divide it by 1.3 and get 2.0. 9+2 = 11. Together with the, it would be 10^11. That how I got 2.0 x 10^11

Hope this Helps, have a nice day!

:)

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seropon [69]
2 .............:)
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4 0
3 years ago
Y is greater than or equal to 3and less than 7
In-s [12.5K]

Answer:

7 > y ≥ 3

Step-by-step explanation:

5 0
3 years ago
What is the solution to this equation?
kirill [66]
The correct answer for the problem above is -23 .

Explanation

1. collect the like terms

2x + x - 11 + 3 - 7x = 15
2x , x , & -7x are like terms
-11 & 3 are like terms

2x + x -7x = -4x
-11 + 3 = -8

2. Move constant to the right-hand side and change its sign .

-4x = 15 + 8
-4x = 23

3. Make the signs on both sides of the equation

-4x = 23 turning into 4x = -23

answer =

4x = -23



7 0
3 years ago
Help asappppp hbshhshshhshshsshshshs
SVEN [57.7K]

9 on the top as well so 9 x 2 18 3x2 6 3

8 0
3 years ago
Suppose a computer manufacturer has the total cost function
S_A_V [24]

Answer:

(a)  P(x) = 300 x - 3600

(b)  P(340) = $ 98400

(c)  At least 12 items must be sold to avoid losing money.

Step-by-step explanation:

Part (a):

The Profit function is the difference between the revenue function (R(x)) and the Cost (C(x)) function:

P(x) = R(x) - C(x)

P(x) = 384 x - [84 x + 3600]

P(x) = 384 x - 84 x - 3600

P(x) = 300 x - 3600

Part (b):

The profit on 340 items is:

P(340) = 300 (340) - 3600

P(340) = 102000 - 3600

P(340) = $ 98400

Part (c):

To avoid losing money, the profit P(x) has to be larger or equal than zero. That is:

P(x) \geq 0

300 x -3600  \geq 0

300 x  \geq 3600

x  \geq 3600/300

x  \geq 12

So at least 12 items must be sold to avoid losing money.

7 0
3 years ago
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