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Nata [24]
3 years ago
9

Plz help me plzz i beg of u

Mathematics
1 answer:
Stells [14]3 years ago
7 0

Answer:

2.0 x 10^11

Step-by-step explanation:

2.6 divide it by 1.3 and get 2.0. 9+2 = 11. Together with the, it would be 10^11. That how I got 2.0 x 10^11

Hope this Helps, have a nice day!

:)

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How do you do this question?
max2010maxim [7]

Answer:

∫₁⁵ 2t (t² + t³) dt

Step-by-step explanation:

The area is ∫ₓ₁ˣ² y dx.  To parameterize, replace x₁ and x₂ with t₁ and t₂.  Replace y = f(x) with y = f(t), and replace dx with (dx/dt) dt.

x = 5 + t², so dx = 2t dt.

∫₁⁵ (t² + t³) (2t dt)

∫₁⁵ 2t (t² + t³) dt

6 0
3 years ago
PLEASE HELP ME ANSWER! im so desperate bro !!
sergey [27]

a)13

b) skewed

c) IQR

d)Sam's observation is correct

e)6.17

Step-by-step explanation:

Step 1 :

From the histogram we can infer that

0 to 2 texts has been sent by 1 student

2 to 4 texts has been sent by 3 student

4 to 6 texts has been sent by 4 student

6 to 8 texts has been sent by 4 student

8 to 10 texts has been sent by 5 student

Step 2:

a)

From step 1 , we can see that there are total of 17 students represented by the histogram

Step 3:

b)

This is a skewed histogram because we have all large values of students on the right of the histogram and smaller values on the left of the histogram.

In symmetrical histogram, there would be large values on the center and the smaller values on both sides.

Step 4:

c)

IQR would be better recommendation for this as this is a skewed histogram

Standard deviation would be recommended for a symmetrical histogram

Step 5:

d)

Total number of students is 17

Number of students who text between 8 to 10 messages is 5

Hence the students who text between 8 and 10 messages is 5/17

which is nearly 1/3 rd of the total students.

Hence Sam's observation is correct

Step 6:

e)

Mean amount of the texts = (1 * 3 + 3* 3 + 5*4 +7*4 + 9* 5) /17 = 6.17

6 0
3 years ago
What do i do with 2 medians
Vitek1552 [10]

Answer:

Add

Divide

Step-by-step explanation:

When you have 2 medians you have to add the 2 numbers together and then divide by two. This is to find the average of the 2 numbers.

8 0
2 years ago
Read 2 more answers
2-[6÷2+{6×1/2+(7/2-3/2)}]​
professor190 [17]

Answer:

-6

Step-by-step explanation:

2 - [6 ÷ 2 + {6 × 1/2 + (7/2 - 3/2)}] =

Follow the correct order of operations.

Do one step at a time and copy everything else each time, so you don't lose track of any operation.

= ​2 - [6 ÷ 2 + {6 × 1/2 + 4/2}]

= 2 - [6 ÷ 2 + {6 × 1/2 + 2}]

= 2 - [6 ÷ 2 + {3 + 2}]

= 2 - [6 ÷ 2 + 5]

= 2 - [3 + 5]

= 2 - 8

= -6

5 0
3 years ago
Read 2 more answers
HELPPPP!!!
Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

4 0
3 years ago
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