All categories

3 years ago

Please help me with this math problem, I am lost

Mathematics

1 answer:

Anarel [89]3 years ago

8 0

Answer:

y= 2x +7

Step-by-step explanation:

<u>Slope-intercept</u><u> </u><u>form</u><u>:</u>

y= mx +c, where m is the slope and c is the y-intercept.

Given that the slope is 2, m=2.

y= 2x +c

Given that the y-intercept is -7, c = -7.

y= 2x +7

You might be interested in

ALGEBRA By bundling cellular, land line, high-speed Internet

Kruka [31]

<h2> My Answer:</h2>

1 303.3$

Okay, I'm not 100% sure it's this because I suck at Math, but I'm 80% sure. I hope you do good on your assignment or test! ^^

6 0

2 years ago

what IS THE FUTURE VALUE OF THE 10% savings from earnings of 36,000 if it earns 6.25% annual interest compounded quarterly for 1

bezimeni [28]

P(1+rt)
Your answer is 69,750.00

4 0

2 years ago

Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to fi

Keith_Richards [23]

Answer:

P(X = 12) = 0.0064.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 30, p = 0.2$

We want P(X = 12). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{30,12}.(0.2)^{12}.(0.8)^{18} = 0.0064$

P(X = 12) = 0.0064.

6 0

2 years ago

The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili

Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .