Answer:
2 (real) solutions.
Step-by-step explanation:
A quadratic always has two solutions, whether they are real or complex.
Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).
In the case of
x^2+3x = 3, or
x² + 3x -3 = 0
we apply the quadratic formula to get
x = (-3 +/- sqrt(3^2+4(1)(3))/2
to give the two solutions
{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}
both of which are real.
Answer:
the answer is c
Step-by-step explanation:
(p - 0.15p) + 1.99
This is the equation to solve.
p minus 15% of p, plus 1.99 for shipping costs.
Line BE and KE are the same length, so set the 2 equations to equal and solve for P.
7p+7 = 37-3p
Add 3 p to both sides:
10p +7 = 37
Subtract 7 from each side:
10p = 30
Divide both sides by 10:
p = 30/10
p = 3
The answer is B.
