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4 years ago

A system of two equations is shown below. What will you need to multiply the

1 answer:

6 0

In order to solve this equation you must eliminate one of the variables.

By multiplying by -3 you eliminate the y variable, making A the correct answer.
-6x-3y=-66
5x+3y=29
-x=-37
x=37

If you would like further explanation let me know. :)

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Which of the following word problems can be solved using the equation 10 x - 15=60

Alja [10]

Answer:

Kit buys

Step-by-step explanation:

im right

8 0

3 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

Learn more here:

brainly.com/question/2962546

4 0

3 years ago

Diagnostic Test

Semmy [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

In a cookie mix, we find spice cookies, snickerdoodle cookies, and no-bake cookies in a ratio of 3:3:5. If a bag of the mix cont

mixas84 [53]

Answer:

see the explaination

Step-by-step explanation:

let x be 3:3:5

3x:3x:5x

3x is splice cookies

3x is snickerdoodle cookies

5x is no bake cookies

where 5x is equal to 45

x is equal to 45÷5=9

so x is equal to 9

now,

3x = 3×9=27

5x = 45 (given)

now add all, total cookies =27+27+45

=99 cookies

so there are total 99 cookies in a cookie mix

5 0

3 years ago

gabriella wants to tile a room with an area of 320 square feet. the width of the room is 4/5 its length. what are the length and

Salsk061 [2.6K]

Assuming the shape of the room is a rectangle :

Area = Width x Length.

Let's call width "w" and length "l" . Now if, the width is 4/5 of the length that means 4/5 times length gives us the width, like this :

$w=\frac { 4 }{ 5 } \cdot l$

As given in the question, area of the rectangle is 320 square feet. And as I said before area of a rectangle can be found by multiplying its length and width.

$w.l=320$

$w=\frac { 4 }{ 5 } \cdot l$ , we can plug w's value in the previous equation to find "l".

$\frac { 4 }{ 5 } \cdot l\cdot l=320\\ \\ \frac { 4 }{ 5 } \cdot { l }^{ 2 }=320\\ \\ { l }^{ 2 }=320\cdot \frac { 5 }{ 4 } \\ \\ { l }^{ 2 }=\frac { 320\cdot 5 }{ 4 } \\ \\ { l }^{ 2 }=\frac { 1600 }{ 4 } \\ \\ { l }^{ 2 }=400\\ \\ \sqrt { { l }^{ 2 } } =\sqrt { 400 } \\ \\ l=20$

Let's plug "l"s value in the equation.

$w.l=320\quad \Longrightarrow \quad w\cdot 20=320\quad \Longrightarrow \quad w=\frac { 320 }{ 20 } \quad \Longrightarrow \quad w=16$

The length is 20 feet and the width is 16 feet.

6 0

4 years ago

Read 2 more answers