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dmitriy555 [2]
3 years ago
5

How can I determine the rate of change in a relationship and how do I explain what it means in terms

Mathematics
1 answer:
vovangra [49]3 years ago
3 0

When you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. f(x) = x2 and f(x + h) = (x + h)2 Therefore, the slope of the secant line between any two points on this function is 2x + h.
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At Happy Pizza, an 8-inch pizza costs $6.00 and a 16-inch pizza costs $14.00. Which pizza is a better deal?​
V125BC [204]

Answer:

8-inch pizza

Step-by-step explanation:

6 0
2 years ago
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What property is 5+0=n
andre [41]

Assuming that you mean to put n instead of 5, this is demonstrating The Identity Property.


The identity property is the property that states that by adding 0 to a number, you don't change the value. For example, 510 + 0 = 510.

4 0
3 years ago
What is the range of the function f(x) = 3x2 + 6x – 8?
oee [108]

f(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by {y|y ≥ k}, where k is the y-coordinate of the vertex.

, written in vertex form is

, where (h, k) = (-1, -11)

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3 0
3 years ago
Simplify the expression shown. You must show your work to receive credit.
ZanzabumX [31]

ANSWER

12 \sqrt{5}

EXPLANATION

The given expression is

\sqrt{2}  \times  \sqrt{72}  \times  \sqrt{5}

The middle radical contains a perfect square.

\sqrt{2}  \times  \sqrt{36 \times 2}  \times  \sqrt{5}

\sqrt{2}  \times  \sqrt{36}   \times  \sqrt{2} \times  \sqrt{5}

6\sqrt{2}  \times  \sqrt{2} \times  \sqrt{5}

Note that:

\sqrt{a}  \times  \sqrt{a}  = a

6\times 2 \sqrt{5}  = 12 \sqrt{5}

4 0
3 years ago
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andrey2020 [161]
The correct answer is B)
Hope this helps!
7 0
3 years ago
Read 2 more answers
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