Question

CONDITIONAL PROBABILITY URGENT?

Answer 1

Let the event $A=\{ Horse \}, B=\{ Female \}$

The the probability of the events

$P(A \cap B)=\frac{2}{14+26} =\frac{1}{20}$

$P( B)=\frac{26}{14+26} =\frac{13}{20}$

The conditional probability

$P(Horse|Female)=P(A|B)=\frac{P(A \cap B)}{P(B)} =\frac{1/20}{13/20} =\frac{1}{13}$