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2 years ago

CONDITIONAL PROBABILITY URGENT?

Mathematics

1 answer:

a_sh-v [17]2 years ago

8 0

Let the event $A=\{ Horse \}, B=\{ Female \}$

The the probability of the events

$P(A \cap B)=\frac{2}{14+26} =\frac{1}{20}$

$P( B)=\frac{26}{14+26} =\frac{13}{20}$

The conditional probability

$P(Horse|Female)=P(A|B)=\frac{P(A \cap B)}{P(B)} =\frac{1/20}{13/20} =\frac{1}{13}$

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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

2 years ago

Una escalera se apoya en una pared con un ángulo de 40º. Si se apoyase con un ángulo de 55º, se conseguiría una altura 35 cm may

sdas [7]

Answer: L ≈ 2.0 m

Step-by-step explanation:

Lsin40 = h

Lsin55 = h + 0.35

Lsin55 = Lsin40 + 0.35

Lsin55 - Lsin40 = 0.35

L(sin55 - sin40) = 0.35

L = 0.35 / (sin55 - sin40)

L = 1.98452 ≈ 2.0 m

3 0

2 years ago

A mallard duck is 56 to 65 cm long if the duck travel 97.8 miles at top speed in 1.5 hours how far did it travel in 1 hour

ra1l [238]

Answer:

They traveled 2.71 in 1 hr

Step-by-step explanation:

97.8 divided by 1.5 then multiply that by 1hr

6 0

2 years ago

When comparing the two sets of data, what is a true statement

PolarNik [594]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Jules has 1200 and is spending 40 per week. kelsey has 400 and is saving 50 a week. in how many weeks, will jules and kelsey hav

expeople1 [14]

After x weeks:
Jules will have: 1,200 + 40 x.
Kelsey will have: 400 + 50 x.
If we want to know in how many weeks will they have the same amount of money, we will make an equation:
400 + 50 x = 1,200 + 40 x
50 x - 40 x = 1,200 - 400
10 x = 800
x = 800 : 10
x = 80
Answer: In 80 weeks they will have the same amount of money.

4 0

2 years ago