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Arada [10]
3 years ago
8

CONDITIONAL PROBABILITY URGENT?

Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Let the event A=\{ Horse \}, B=\{ Female \}

The the probability of the events

P(A \cap B)=\frac{2}{14+26} =\frac{1}{20}

P( B)=\frac{26}{14+26} =\frac{13}{20}

The conditional probability

P(Horse|Female)=P(A|B)=\frac{P(A \cap B)}{P(B)} =\frac{1/20}{13/20} =\frac{1}{13}

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