I think there are two solutions, 63 or 147:
63 = 3² x 7, factors 1 | 3 | 7 | 9 | 21 | 63<span>
147 = 3 x 7</span>², factors 1 | 3 | 7 | 21 | 49 | 147
Answer:
It's A, Because it makes the most sense in this algebra question.
Step-by-step explanation:
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It will come out to a flat number like 10 20 30 40 ect and the counterfeit will have a 1 at the end such as 11 21 31 41.
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2
X - 4 when you use the foil method or multiplication
I would say the first choose that the vertical axis should use $0.50 intervals instead of $1.
Because this would make it much easier to read and understand and would it would also be more accurate.
