Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Answer:
Step-by-step explanation:
Sum of interior angle of any polygon =(n-2) × 180°where n represents the number of sides in any polygon.
Or 1260 =(n-2)x180
Dividing both sides by 180:
7=n-2
Adding both sides by 2 we have :
n=9.
Hence a nanogon will have the sum of interior angles as 1260°.
Answer:
3
Step-by-step explanation:
The measure of the slope is 
at x = a
Differentiate using the power rule
(a
) = na
Given
y = x³ - 1, then
= 3x²
The slope at (1, 0) is
= 3(1)² = 3
P + s = 200......p = 200 - s
20p + 15s = 3400
20(200 - s) + 15s = 3400
4000 - 20s + 15s = 3400
-20s + 15s = 3400 - 4000
-5s = - 600
s = -600/-5
s = 120 <=== there were 120 standard tickets sold
p + s = 200
p + 120 = 200
p = 200 - 120
p = 80 <=== there were 80 premium tickets sold
the answer to your question is 13 mm
