Answer : -19.6
Explanation : We can calculate this using the combine equation of boiling point and depression in freezing point and obtain a combined equation which is
∆T(f) = ∆T(b) x {K(f) / K(b)} ;
Where ∆T(f) is depression in freezing point,
∆T(b) is elevation in boiling point,
K(f) is cryoscopic constant for water it is 1.86
K(b) is ebullioscopic constant for water it is 0.512
So we can solve the equation,
∆T(f) = (105.4 -100) X 
= 19.6
So when we have the freezing point depression as 19.6,
we know water freezes at 0° C so the freezing point will be 0 - 19.6 = -19.6 °C
Answer:
As it is possible to observe in the drawing of the resonance structure of nitromethane, both oxygen atoms have the same negative charge.
Explanation:
A resonance structure is the molecular bonding system in which a hybrid, called a resonance, is formed from two or more Lewis structures that have different electronic distributions.
The resonance effect is given by the delocalization of electrons, which are not at a fixed point but are distributed homogeneously in the molecule as we can see in the nitromethane, providing stability. So the more resonance structures the molecule has, the more stable it will be.
Answer:
what is the question?
Explanation:
if you tell me ill update it if i got the info
Answer:
230
Explanation:
Given equilibrium conditions, if a system is at equilibrium, this means the rate of a forward reaction becomes equal to the rate of a reverse reaction and the concentrations of each species become constant (stop to change).
This is defined by the equilibrium constant which defines the concentrations at equilibrium. For the given reaction, the equilibrium constant can be described as the ratio between the concentrations of products (raised to the power of their coefficients) and the concentrations of reactants (raised to the power of their coefficients):
![K_{eq}=\frac{[N_2][H_2]^3}{[NH_3]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BN_2%5D%5BH_2%5D%5E3%7D%7B%5BNH_3%5D%5E2%7D)
Q, on the other hand, is a reaction quotient. It is used only to determine where the equilibrium will shift when the system is actually not at equilibrium. The expression or Q is exactly same, but concentrations used would be non-equilibrium concentrations. There are three cases:
: in this case, equilibrium shifts towards the formation of products;
: the system is at equilibrium;
: equilibrium shifts towards the formation of reactants.
Looking at the context of our problem, since this system is at equilibrium, then Q = K = 230.
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