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WARRIOR [948]
3 years ago
15

If 3.0×105 j of heat are added to the ice, what is the final temperature of the system?

Chemistry
1 answer:
lara [203]3 years ago
3 0
A wet-chemistry biochemical analyzer<span> was assessed for in-practice veterinary use. Its small size may mean a cost-effective method for low-throughput in-house biochemical analyses for first-opinion practice. The objectives of our study were to determine imprecision, total observed error, and acceptability of the </span>analyzer<span> for measurement of common canine and feline </span>serum<span> analytes, and to compare clinical </span>sample<span> results to those from a commercial reference </span>analyzer<span>. Imprecision was determined by within- and between-run repeatability for canine and feline pooled </span>samples<span>, and manufacturer-supplied quality control material (QCM). Total observed error (TEobs) was determined for pooled </span>samples<span> and QCM. Performance was assessed for canine and feline pooled </span>samples<span> by sigma metric determination. Agreement and errors between the in-practice and reference </span>analyzers<span> were determined for canine and feline clinical </span>samples<span> by Bland-Altman and Deming regression analyses. Within- and between-run precision was high for most analytes, and TEobs(%) was mostly lower than total allowable error. Performance based on sigma metrics was good (σ > 4) for many analytes and marginal (σ > 3) for most of the remainder. Correlation between the </span>analyzers<span> was very high for most canine analytes and high for most feline analytes. Between-</span>analyzer<span> bias was generally attributed to high constant error. The in-practice </span>analyzer<span> showed good overall performance, with only calcium and phosphate analyses identified as significantly problematic. Agreement for most analytes was insufficient for transposition of reference intervals, and we recommend that in-practice-specific reference intervals be established in the laboratory.</span>
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Maurinko [17]
Hello friends..

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A/1 * B/C =D
Novay_Z [31]
<h3>Answer:</h3>

                  0.64 Moles of Propane

<h3>Explanation:</h3>

Data:

         Moles of Carbon  =  1.5 mol

         Conversion factor  =  7 mol C produces = 3 mol of Propane

Solution:

             As we know,

                7 moles of Carbon produces =  3 moles of Propane

Then,

            1.5 moles of Carbon will produce  =  X moles of Propane

Solving for X,

                     X =  (1.5 moles × 3 moles) ÷ 7 moles

                     X  =  0.6428571 moles of Propane

Or rounded to two significant figures,

                     X =  0.64 Moles of Propane

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Answer:

The Atlantic Ocean.

Explanation:

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