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vladimir2022 [97]
2 years ago
8

Help pls I will mark brainlest​

Chemistry
1 answer:
defon2 years ago
4 0

Resources found in lithosphere: gold and iron etc

Resources found in atmosphere: Water vapor, gases etc.

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3 years ago
What volume of 0.585 m ca(oh)2 would be needed to neutralize 15.8 l of 1.51 m hcl?
SpyIntel [72]
When the balanced reaction equation is:

2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l)

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2:1

∴ the volume of Ca(OH)2 = 15.8 L HCl * 1.51 m HCl * (1mol Ca(OH)2/ 2mol HCl) *                                           (1L ca(OH)2/0.585 mol Ca(OH)2 

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likoan [24]

Answer:

first one-liquids dont have a fixed shape and solids do

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