To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that

and the exponent

are divisible by index

. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is:
Y = kx ⇒ k = y/x = 2/(-3) = -2/3
Answer: k = -2/3
To find the median of the data set, we must first order them from lowest to highest in increasing order. Let's rearrange them in that way:
{17, 23, 30, 40, 44, 44}
Then we begin by crossing one off from each side, until we get to the middle. However, we see that our middle here is both 30 and 40.
What we do in a case like this is add up the two numbers and divide by 2 (essentially find the mean of the two middlemost numbers). Let's do that now:


So now we know that
the median of the set of data is 35.
Answer:
108
Step-by-step explanation:
add all of the numbers together and thats what you get :)