Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=

so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=

x=

x=

x=

x=

there are no real numbers that satisfy this
Step-by-step explanation:
Use the Rational Zero Theorem to list all possible rational zeros of the function.
Use synthetic division to evaluate a given possible zero by synthetically dividing the candidate into the polynomial. ...
Repeat step two using the quotient found with synthetic division. ...
Find the zeros of the quadratic function.
Answer:

Step-by-step explanation:
Hi there!

Solve -2^2:

Divide both sides by -4:

Subtract 10 from both sides:

Divide both sides by -5:

Therefore, x = 7.
I hope this helps!
Answer:
24
Step-by-step explanation:
60% is equal to 3/5. So, we can divide 15 by 5 to get 3 and multiply 3 by 3 to get 9. Then add 9 to the 15 to get 24, Alternatively you can multiply 15 by 1.6