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Ber [7]
3 years ago
11

The quotient of two rational numbers is positive. What can you conclude about the signs of the dividend and the divisor? That’s

us my question it’s confusing please someone help meee I’m in grade 7
Mathematics
1 answer:
satela [25.4K]3 years ago
6 0

Answer:

The divisor and dividend have the same signs.

Step-by-step explanation:

Let's look at all of the possible outcomes of dividing with different signs.

Positive / positive = positive

Positive / negative = negative

Negative / positive = negative

Negative / negative = positive

We can see that whenever the signs are the same, the quotient is positive.

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Please help!!!!!!! Please help!!!!!! Please help!!!!!!
Nitella [24]

Answers:

  1. Discrete
  2. Continuous
  3. Discrete
  4. Continuous

==============================================

Explanations:

  1. This is discrete because we can't have half a basketball, or any non-whole decimal value to represent the number of basketballs. We can only consider positive whole numbers {1,2,3,4,...}. A discrete set like this has gaps between items. In other words, the midpoint of 2 and 3 (the value 2.5) isn't a valid number of basketballs.
  2. This is continuous because time values are continuous. We can take any two different markers in time, and find a midpoint between them. For example, the midpoint of 5 minutes and 17 minutes is 11 minutes since (5+17)/2 = 22/2 = 11. Continuous sets like this do not have any gaps between items. We can consider this to be densely packed.
  3. This is the same as problem 1, so we have another discrete function. You either score a bullseye or you don't. We can't score half a bullseye. The only possible values are {1,2,3,4,...}
  4. This is similar to problem 2. This function is continuous. Pick any two different positive real numbers to represent the amount of gallons of water. You will always be able to find a midpoint between those values (eg: we can have half a gallon) and such a measurement makes sense.

So in short, always try to ask the question: Can I pick two different values, compute the midpoint, and have that midpoint make sense? If so, then you're dealing with a continuous variable. Otherwise, the data is discrete.

7 0
3 years ago
Can someone please help with this ?
olga nikolaevna [1]

Answer:1/32

Step-by-step explanation:

8 0
3 years ago
If (-2,4) are the coordinates of a point on the line whose equation is y=Mx+1 , what is the slope of the line?
horrorfan [7]

Slope of the line is -3/2

Step-by-step explanation:

  • Step 1: Given that (-2, 4) is a point on the line y = mx + 1, find slope m.

Since the point is on the line, the coordinates will satisfy the equation.

⇒ 4 = m × -2 + 1

⇒ 4 = -2m + 1

⇒ 3 = -2m

∴ m = -3/2

5 0
3 years ago
Draw place value disks on the place value chart 0.7 ÷ 4
Mama L [17]
Change 0.7 to 7/10 and 4 to 1/4,so it'll be 7/10x1/4, then find least common denominator, 40.change fractions to 28/40x10/40=280/40=70
4 0
3 years ago
Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod
goblinko [34]

(2+3)^{-1}\equiv5^{-1}\pmod7 is the number <em>L</em> such that

5L\equiv1\pmod7

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

2a\equiv1\pmod7\implies a\equiv4\pmod7

since 2*4 = 8, whose residue is 1 mod 7;

3b\equiv1\pmod7\implies b\equiv5\pmod7

which we got for free by finding the inverse of 5 earlier. So

2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7

and so <em>R</em> = 2.

Then <em>L</em> - <em>R</em> = 1.

6 0
3 years ago
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