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OLga [1]
3 years ago
6

The charges and sizes of the ions in an ionic compound affect the strength of the electrostatic attraction holding that compound

together. Based on ion charges and relative ion sizes, rank these ionic compounds by their expected melting points from highest to a. SrCl2 b. CsBr c. RbCl d. SrS
Chemistry
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

order = SrS > SrCl2 > RbCl > CsBr

Explanation:

Comparison of the melting points of compounds is basically dependent on the charge on their cation and anion, the more the charges on the cation and anion, the stronger and greater the force of attraction and as such the melting point will be relatively higher as well.

The ionic radii is also another factor to be considered, the more the distance between ions, the lesser the bond strength and the lesser the melting point.

from the options, in terms of ionic radii SrS > SrCl2 and RbCl > CsBr

also both SrS and SrCl2 have more charges on their ions compared to RbCl and CsBr and as such the arrangement of the highest melting point will be in the order SrS > SrCl2 > RbCl > CsBr.

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High concentrations of ammonia (NH3), nitrite ion, and nitrate ion in water can kill fish. Lethal concentrations of these specie
kykrilka [37]

Explanation:

It is known that molality is the number of moles present in kg of solution.

Mathematically,  Molality = \frac{\text{no. of moles of solute}}{\text{mass of solvent in Kg}}

The given data is as follows.

Molar mass of ammonia = 17 g/mol

Concentration = 1.002 mg/L = \frac{0.001002 g/L}{17 g/mol}

                        = 5.89 \times 10^{-4} mol/L

Also,    density = \frac{1 g}{mL} = 1 kg/L

Therefore, molality will be calculated as follows.

        Molality = \frac{5.89 \times 10^{-4} mol/L}{1 kg/L}

                      = 5.89 \times 10^{-4} mol/kg

And,

Molar mass of nitrite = 46 g/mol

Concentration = 0.387 mg/L = \frac{0.000412 g/L}{46 g/mol}

                        = 8.956 \times 10^{-6} mol/L

And, density = \frac{1 g}{mL} = 1 kg/L

Hence, molality = \frac{8.956 \times 10^{-6} mol/L}{1 kg/L}

                          = 8.956 \times 10^{-6} mol/kg  

Now, Molar mass of nitarte = 62 g/mol

      Concentration = 1352.2 mg/L

                              = \frac{1.3522 g/L}{62 g/mol}

                              = 0.02181 mol/L

Also, density = \frac{1 g}{mL} = 1 kg/L

Hence, molality will be calculated as follows.

         Molality = \frac{0.02181 mol/L}{1 kg/L}

                       = 0.02181 mol/kg

Therefore, molality of given species is 5.89 \times 10^{-4} mol/kg  for ammonia, 8.956 \times 10^{-6} mol/kg  for nitrite, and 0.02181 mol/kg for nitrate ion.

7 0
3 years ago
Identifying compounds Caffeine is the most widely used psychoactive drug in the world and is found in coffee beans, tea leaves,
Marina CMI [18]

Answer:

Matter

Compound

Explanation:

Caffeine is NOT an Element, because it is formed by different elements (C, H, N, and O).

Caffeine is NOT an Isotope, because this only applies to elements with the same atomic number but different mass number.

Caffeine is Matter because it has mass and occupies space by having volume.

Caffeine is a Compound because it has a formula with a <em>definite constant composition</em> of different elements.

4 0
3 years ago
Why do magnesium, phosphorus, and zinc exhibit slightly higher first ionization energies than the general trend within each of t
Lapatulllka [165]
Because they are farther across the periodic table<span />
8 0
3 years ago
List the substances Ar, Cl2, CH4, and CH3COOH, in order of increasing strength of intermolecular attractions. List the substance
Viefleur [7K]

Answer:

Order of increasing strength of intermolecular attraction:

CH_3COOH > Cl_2 > CH_4 > Ar

Explanation:

CH_3COOH can form hydrogen bond as H atom is attached with electronegative atom O.

Rest three, Cl_2,  CH_4,  Ar are non-polar molecules.

In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence, CH_3COOH has strongest intermolecular attractions.

Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.

Molecular size and mass of Cl_2 is high as compared to CH_4.

van der Waals intermolecular forces of attraction increases with increase in size.

Therefore,

Order of increasing strength of intermolecular attraction will be:

CH_3COOH > Cl_2 > CH_4 > Ar

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