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OLga [1]
3 years ago
6

The charges and sizes of the ions in an ionic compound affect the strength of the electrostatic attraction holding that compound

together. Based on ion charges and relative ion sizes, rank these ionic compounds by their expected melting points from highest to a. SrCl2 b. CsBr c. RbCl d. SrS
Chemistry
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

order = SrS > SrCl2 > RbCl > CsBr

Explanation:

Comparison of the melting points of compounds is basically dependent on the charge on their cation and anion, the more the charges on the cation and anion, the stronger and greater the force of attraction and as such the melting point will be relatively higher as well.

The ionic radii is also another factor to be considered, the more the distance between ions, the lesser the bond strength and the lesser the melting point.

from the options, in terms of ionic radii SrS > SrCl2 and RbCl > CsBr

also both SrS and SrCl2 have more charges on their ions compared to RbCl and CsBr and as such the arrangement of the highest melting point will be in the order SrS > SrCl2 > RbCl > CsBr.

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Explanation:

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The concentration of HCl can be determined by titration with a primary standard such as Na2CO3 (sodium carbonate). The titration
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Answer:

The concentration of HCl is 0.275 M

Explanation:

<u>Step 1:</u> Data given

Mass of Na2CO3 = 0.521 grams

Molar mass of Na2CO3 = 105.99 g/mol

Volume of HCl = 35.7 mL

<u>Step 2: </u>The balanced equation:

2HCl + Na2CO3 → 2NaCl + CO2 + H2O

CO3(2-) + 2H+ ---> H2O + CO2

<u>Step 3</u>: Calculate moles of Na2CO3

Moles Na2CO3 = mass Na2CO3 / Molar mass Na2CO3

Moles Na2CO3 = 0.521 grams / 105.99 g/mol

Moles Na2CO3 = 0.0049 moles

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For 1 mol of Na2CO3 consumed, we need 2 moles of HCl

moles of HCL = 2 * 0.0049 = 0.0098 moles HCl

<u>Step 5:</u> Calculate molarity of HCl

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<h2>Answer with explanation </h2>

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