<u>Answer:</u>
<u>For a:</u> The equilibrium mixture contains primarily reactants.
<u>For b:</u> The equilibrium mixture contains primarily products.
<u>Explanation:</u>
There are 3 conditions:
- When ; the reaction is product favored.
- When ; the reaction is reactant favored.
- When ; the reaction is in equilibrium.
For the given chemical reactions:
The chemical equation follows:
The expression of for above reaction follows:
As, , the reaction will be favored on the reactant side.
Hence, the equilibrium mixture contains primarily reactants.
The chemical equation follows:
The expression of for above reaction follows:
As, , the reaction will be favored on the product side.
Hence, the equilibrium mixture contains primarily products.
Answer: 2.74 litres
Explanation:
Given that,
Original pressure of balloon (P1) = 100.0 kPa
Original volume of balloon (V1) = 2.29 litres
New pressure of balloon (P2) = 83.5 kPa
New volume of balloon (V2) = ?
Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law
P1V1 = P2V2
100 kPa x 2.29 L = 83.5 kPa x V2
229 kPa•L = 83.5 kPa•V2
Divide both sides by 83.5 kPa
229 kPa•L/83.5 kPa = 83.5 kPa•V2/ 83.5 kPa
2.74 L = V2
Thus, the new volume of the balloon is 2.74 litres
one mole
If we look this number up for helium, we find that helium has a molar mass of 4.0 grams per mole. So one mole of helium has a mass of 4.0 grams. We can use the molar mass as a conversion factor. Two moles of helium times four grams of helium per mole of helium is equal to eight grams of helium.