How many grams of potassium nitrate (KNO3) are required to prepare 0.250L of a 0.700 M
1 answer:
You might be interested in
Answer:
<h2>Density = 10.01 g/cm³</h2>Explanation:
The density of a substance can be found by using the formula
<h3>From the question
mass of metal = 54.52 g
Volume of metal = new volume - original volume of water in the cylinder
That's
new volume = 28.85 mL
original volume of water = 23.44 mL
Volume of metal
= 28.85 - 23.44 = 5.41 mL
Next we convert the volume from mL to cm³
1 mL = 1 cm³
5.41 mL = 5.41 cm³
Substitute the values into the above formula and solve
That's
<h3>We have the final answer as
<h3>Density = 10.01 g/cm³</h3>Hope this helps you