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DaniilM [7]
3 years ago
15

What is the mass of 1 mole of magnesium (Mg)? Express your answer to four significant figures.

Chemistry
2 answers:
Kay [80]3 years ago
6 0

Answer:

24.305 grams

Explanation:

matrenka [14]3 years ago
3 0

Answer:

24.31 g

Explanation:

The mass of 1 mole of any compound is it's molar mass. The molar mass of Magnesium is given as; 24.3050g/mol

Mass = Number of moles * Molar mass

Mass = 1 * 24.3050

Mass = 24.3050g

Upon conversion to four significant figures, it becomes;

Mass = 24.31g

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ivanzaharov [21]
It is true

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4 0
3 years ago
Liquid bromine is added to sodium iodide crystals
gulaghasi [49]

The following chemical reaction will occur:

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

Explanation:

Because the bromide (Br₂) have a higher reactivity than iodide (I₂) it is able the remove the iodide from its salts. So the bromide will react with sodium iodine (NaI) to produce sodium bromide (NaBr) and iodine.

The chemical reaction is:

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

where:

(l) - liquid

(s) - solid

Learn more about:

balancing chemical equations

brainly.com/question/13971935

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6 0
3 years ago
In the Mond process for the purification of nickel, carbon monoxide is reacted with heated nickel to produce Ni(CO)4, which is a
igor_vitrenko [27]

<u>Answer:</u> The equilibrium constant for this reaction is 1.068\times 10^{6}

<u>Explanation:</u>

The equation used to calculate standard Gibbs free change is of a reaction is:

\Delta G^o_{rxn}=\sum [n\times \Delta G^o_{(product)}]-\sum [n\times \Delta G^o_{(reactant)}]

For the given chemical reaction:

Ni(s)+4CO(g)\rightleftharpoons Ni(CO)_4(g)

The equation for the standard Gibbs free change of the above reaction is:

\Delta G^o_{rxn}=[(1\times \Delta G^o_{(Ni(CO)_4(g))})]-[(1\times \Delta G^o_{(Ni(s))})+(4\times \Delta G^o_{(CO(g))})]

We are given:

\Delta G^o_{(Ni(CO)_4(g))}=-587.4kJ/mol\\\Delta G^o_{(Ni(s))}=0kJ/mol\\\Delta G^o_{(CO(g))}=-137.3kJ/mol

Putting values in above equation, we get:

\Delta G^o_{rxn}=[(1\times (-587.4))]-[(1\times (0))+(4\times (-137.3))]\\\\\Delta G^o_{rxn}=-38.2kJ/mol

To calculate the equilibrium constant (at 58°C) for given value of Gibbs free energy, we use the relation:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = Standard Gibbs free energy = -38.2 kJ/mol = -38200 J/mol  (Conversion factor: 1 kJ = 1000 J )

R = Gas constant = 8.314 J/K mol

T = temperature = 58^oC=[273+58]K=331K

K_{eq} = equilibrium constant at 58°C = ?

Putting values in above equation, we get:

-38200J/mol=-(8.314J/Kmol)\times 331K\times \ln K_{eq}\\\\K_{eq}=e^{13.881}=1.068\times 10^{6}

Hence, the equilibrium constant for this reaction is 1.068\times 10^{6}

4 0
3 years ago
If measuring experimental results, what can you predict about the work output of a 1200 watt hair dryer? the work output of the
eimsori [14]

Answer: first option, the work output of the hairdryer will be less than the work input.


Explanation:


1) The work output measured in watts is the power of hair dryer measured in joules per second.


2) The hair dryer converts electrical energy from the wall outlet to mechanical and thermal energy: hot wind.


3) Nevertheless, you can never expect a 100% efficiency of the machines: due to friction, some energy is converted into useless energy.


So, efiiviency = power output / power input< 1 ⇒


power output = work output / time


input power = work input / time


⇒ work output / work input < 1


⇒ work output < work input.


Which is the first option: the work output of the hairdryer will be less than the work input

6 0
3 years ago
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a substance has neither of fixed shape nor a fixed volume state whether it is a solid or liquid or gas​
tensa zangetsu [6.8K]
A gas because if you freeze water, it turns into a shape as where gas can’t be frozen
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4 years ago
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