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3 years ago

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What are the vertical asymptotes of the function f(x) = the quantity of 2 x plus 8, all over x squared plus 5 x plus 6? x = −3 a

nd x = −2 x = −3 and x = 2 x = 1 and x = −2 x = 1 and x = 2?

1 answer:

lbvjy [14]3 years ago

3 0

For this question the answer would be x=-3 and x=-2

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PLEASE ANSWER WILL MARK BRAINLIEST!!!

seropon [69]

Answer:

0.987750947 miles

Step-by-step explanation:

first you find how many inches are in a mile and there are 63360 inches in a mile

2nd you minus 63360 - 776.1 = 62583.9 then you get 62583.9 and put it in miles and your answer is 0.987750947 miles

3 0

1 year ago

How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size and the height is quadrup

vesna_86 [32]

Volume of a cylinder = π r² h

Let us assume the following values:
radius = 9
height = 10

Volume = 3.14 * 9² * 10
= 3.14 * 81 *10
Volume = 2,543.40

Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40

Volume = π r² h
= 3.14 * 2² * 40
= 3.14 * 4 * 40
Volume = 502.40

Original volume = 2543.40 V.S. Volume after change = 502.40

The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times.

4 0

2 years ago

2 of 8<br> =<br> Given that y = 10 cm and 0 = 19°, work out x rounded to 1 DP.<br> у<br> х<br> oo

Drupady [299]

Answer:

x = 3.255 cm

Step-by-step explanation:

Given:

⇒ y = 10cm

⇒ θ = 19

To find:

⇒ Value of "n"

Solution

⇒ By Pythagoras theorem

⇒ Δ Sin θ = n/y

⇒ sin 19° = n/10

⇒ 0.3255 = n/10

⇒ n = 0.3255 × 10

⇒ n = 3.255 cm

Hence, the answer is = n = 3.255 cm.

8 0

2 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago

The equation of a line given two points needs to be found. Samuel claims that slope-intercept form will generate the equation an

Zigmanuir [339]

The answer is:put the equation xa+yb=1 to the slope intercept form and find its slope and y-intercept.

3 0

3 years ago