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3 years ago

Kay walks upstairs to make her legs stronger. Every day at work, she

Mathematics

2 answers:

xeze [42]3 years ago

4 0

Answer: 585 steps in 5 days

Step-by-step explanation:

9 flights up daily

13 steps per flight

5 days

9x13x5=585

maksim [4K]3 years ago

4 0

Answer:

Step-by-step explanation: first multiply 9 times 13. then that times 5 and you get 675 steps

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the interest earned on an account varies directly with the balance in the account. if an account with a balance of $200 earns $1

liq [111]

Answer:

$\$31.25$

Step-by-step explanation:

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Let

y-------> the interest earned on an account

x------> the balance in the account

step 1

Find the constant k of proportionality

For $x=\$200,y=\$12.50$

$k=y/x$

substitute the values

$k=12.50/200=0.0625$

The equation is

$y=0.0625x$

step 2

Find the amount of interest earned on an account with a balance of $500

For $x=\$500$ substitute in the equation and solve for y

$y=0.0625(500)=\$31.25$

6 0

3 years ago

Please answer :) it seems like something that should be easy but I totally forgot how to do it!

Gwar [14]

It's essentially asking for the value of y on the graph of function f(x) when x is equal to -4.

Graphically, we can see that when x = -4, y would be 1.

If you had to do this algebraically with an equation for the function, just slot the value of -4 in for x, to find the value for y.

7 0

4 years ago

Read 2 more answers

1 + 1⁄2 + 1⁄4 + 1⁄8 + 1⁄16 + 1⁄32 + 1⁄64. . . Notice that the denominator of each fraction in the sum is twice the denominator t

bulgar [2K]

$a_1=1\\ q=\dfrac{1}{2}$

$|q|$ therefore, the sum of this infinite geometric series can be calculated using the formula $S=\dfrac{a}{1-q}$ .

So, $S=\dfrac{1}{1-\dfrac{1}{2}}=\dfrac{1}{\dfrac{1}{2}}=2$

If 2 is the sum of this infinite series, then you'll never reach it.

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3 years ago

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garik1379 [7]

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3 years ago

An oil storage tank ruptures at time t = 0 and oil leaks from the tank at a rate of

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$\displaystyle\int_0^{60}r(t)\,\mathrm dt=\int_0^{60}80e^{-0.01t}\,\mathrm dt$

Let $u=-0.01t$ so that $-100\mathrm du=\mathrm dt$ . Then the integral becomes

$\displaystyle-8000\int_0^{-0.6}e^u\,\mathrm du=8000\int_{-0.6}^0e^u\,\mathrm du=8000(e^0-e^{-0.6})\approx3610\text{ L}$

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4 years ago