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2 years ago

(3,y) (1,4) m= -2 what is the value of y if the line through the two given points is to have indicated slope

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

5 0

Answer:

y=0

Step-by-step explanation:

The equation for the slope is

m = ( y2-y1)/(x2-x1)

-2 = (4-y)/(1-3)

-2 = (4-y)/-2

Multiply each side by -2

4 = 4-y

Subtract 4 from each side

4-4 = 4-y-4

0 = -y

0=y

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The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.18 millimeters and a standard deviat

dimulka [17.4K]

As per the concept of normal distribution, the two diameters of the bolt that has separate the top 3% and the bottom 3% are 5.2836 mm and 5.0764 mm respectively .

Normal distribution:

Normal distribution means the probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean and it has the bell shaped curve.

Given,

The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.18 millimeters and a standard deviation of 0.07 millimeters.

Here we need to find the two diameters that separate the top 3% and the bottom 3% and these diameters could serve as limits used to identify which bolts should be rejected. we have also round off the result into nearest hundredth.

Here we have the given question with the values of,

The value of Mean is 5.18 millimeters

The value of Standard deviation is 0.07 millimeters.

Here we have to consider the following two cases, they are.

Case 1

We need to find x₁ such that that is P(X > x₁) = 3% when we convert it into decimal then we get P (X > x₁) = 0.03

So, as per the probability,

P (X ≤ x₁) = 1 - 0.03 = 0.97

So, z corresponding to the value of p = 0.97 is 1.48

Apply the given values to the formula of normal distribution then we get,

=> 1.48 = (x₁ - 5.18) /0.07

=> 0.1036 = x₁ - 5.18

Therefore, the value of x₁ is 5.2836

So, the diameter of the both with separate top 3% is 5.2836.

Case 2:

Next we have to take P(X < x₂) = 3% when we convert it into decimal then we get P (X < x₂) = 0.03

So, as per the given probability, the value of

P (X ≤ x₂) = 1 - 0.03 = 0.97

So, z corresponding to but here we have to use the negative because of the less than concept p = 0.97 is -1.48

Apply the values on the formula of normal distribution then we get,

-1.48 = (x₂ - 5.18) /0.07

Move the value to the other side

-0.1036 = x₂ - 5.18

When we simplify it,

x₂ = 5.0764

So, the diameter of the both with separate bottom 3% is 5.0764

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A stadium has a a central rectangular area 125m long by 80m wide.there are two semi circular ends.a running track goes all the w

Fudgin [204]

a)The total inside length of the curved ends of the track will be 25.13 meters

b)The total distance around the inside of the track will be 275.13 meters

c)The area inside the track is 10050 square meters.

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Given that:-

A stadium has a central rectangular area 125m long by 80m wide. there are two semi-circular ends. a running track goes all the way around.

a) what is the total inside length of the curved ends of the track?

The length of the curved track means it is a perimeter of the circle so the radius of the semicircle will be 4 meters.

So the length will be = π r + πr = 2 πr

= 2 x π x 4 = 25.13

b) what is the total distance around the inside of the track?

The total distance of the track will be the sum of the length of the two semicircles and the longer side of the rectangle.

Total length = 125 + 125 + 25.13

= 275.13 meters

c) what is the area inside of the track?

The area will be equal to the area of the two semicircular tracks and the rectangular track.

Total Area = Area of semicircle + Area of semicircle + Area of rectangle

= ( π/2 ) r² + (π/2) r² + ( L x W )

= π r² + ( L x W)

= π ( 4 )² + ( 125 x 8 )

= 10050.26 square meters.

Therefore the total inside length of the curved ends of the track will be 25.13 meters. The total distance around the inside of the track will be 275.13 meters. The area inside the track is 10050 square meters.

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