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4 years ago

12

What is 0.12 with 12 repeating as a fraction

2 answers:

strojnjashka [21]4 years ago

8 0

12/99 is the fraction form

noname [10]4 years ago

7 0

Rewrite the decimal number as a fraction with 1 in the denominator<span>0.12=<span>0.121</span></span>Multiply to remove 2 decimal places. Here, you multiply top and bottom by 102 = 100<span><span>0.121</span>×<span>100/100</span>=<span>12/100</span></span>Find the Greatest Common Factor (GCF) of 12 and 100, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 4,<span><span><span>12÷4</span><span>/100÷4</span></span>=<span>3/25</span></span>Therefore<span>X=<span>3/25</span></span>In conclusion,<span>0.12=<span>3<span>/25</span></span></span>

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3 years ago

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ollegr [7]

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Step-by-step explanation:

We are given that $\alpha$ and $\beta$ are the zeroes of the polynomial $6y^2-7y+2$

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General quadratic equation

$x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes$

We get

$\alpha+\beta=\frac{7}{6}$

$\alpha \beta=\frac{1}{3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3$

Substitute the values

$y^2-(7/2)y+3=0$

$2y^2-7y+6=0$

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4 years ago

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NikAS [45]

Answer:

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57.5 x 2=115 so that is the arc for CE

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