F(x) = 3x^2+6x-2
= 3(x^2+2x-2/3)
= 3(x^2 +2x + 1 - 1 - 2/3)
= 3((x+1)^2 - 1 - 2/3)
= 3((x+1)^2 -5/3))
= 3(x+1)^2 - 5
So our function is in the form:
f(x) = 3(x+1)^2 - 5
where a = 3, h = -1, k = -5
Follow the rules of PEMDAS:
42/(15-8)
42/7
6
point slope form means (y-y1)=m(x-x1)
so u need to find the slope gradient from those 2 points
m=y2-y1/x2-x1
=-6-6/11-7
=-12/4
=-3
and finally x1,y1=7,6
(y-y1) =m(x-x1)
(y-6) =-3(x-7)
