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Alenkinab [10]
3 years ago
15

Find the distance from the point (6,10) to the line y=-x to the nearest tenth

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
4 0
<span>points (6,10)
</span>y = -x
x + y = 0

distance = lax1 + by1 + cl/√(a^2 + b^2)
 = l1(6) + 1(10) + 0l/√(1^2 + 1^2)
 = l6 + 10 + 0l/√(1 + 1)
 = l16l/√2
 = 16/√2
 = 8 .2/√2
 = 8 . √2.√2/√2
= 8√2
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