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Sveta_85 [38]
3 years ago
10

What can I multiply 4/3 by to make it 1⅓​, jk what's up

Mathematics
1 answer:
Simora [160]3 years ago
7 0

1.<u>3 </u>x 1= 1.<u>3 </u>hope this helped

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Juan used 2 pieces of rope for a project. If the pieces are 9.832 meters and 2.25 meters. How much rope did Juan use?
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(The answer is 12.082.) Juan used 12.082 meters of rope.
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2 years ago
Refer to Expression 1 and Expression 2.
TiliK225 [7]

Expression 1 is 25

6*7-3^2*9+4^3

First simplify all the exponents to get 6*7 - 9 * 9 + 64 and then multiply the two numbers to get 42 - 81 + 64 and just add = 25

For expression 2, if you put the parantheses around (5+4)*2+6-2*2-1, it'll be 19

(5+4)*2+6-2*2-1

9*2+6-2*2-1

18+6-4-1

24-5

19

Remember order of operations

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2 years ago
-63<br> —— = -7 what’s the error <br> -9
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Answer:

One of the negatives must go

Step-by-step explanation:

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2 years ago
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4 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
2 years ago
Read 2 more answers
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