A population of 1,500 insects grows exponentially by a factor of 3 every week. Select all equations that represent or approximat

Question

1 year ago

13

e the population, p. as a function of time in days.t, since the population was 1,500.

1 answer:

Andreas93 [3] · Answer 1 · 2022-11-28T03:36:21+03:00

Answer:

FV(p)= PV*(1 + g)^t

Step-by-step explanation:

Giving the following information:

Number of insects (PV)= 1,500

Increase rate= 3 weekly

First, we need to calculate the daily growth rate:

Daily rate (g)= [3^(1/7)] - 1

Daily rate (g)= 0.16993

Now, by using the following formula, we can determine the population p in any given day t:

FV(p)= PV*(1 + g)^t

For, example after 7 days:

FV(p)= 1,500*(1.16993^7)

FV(p)= 4,500

For example, after 10 days:

FV(p)= 1,500*(1.16993^10)

FV(p)= 7,206