Answer:
A. 
B. Yes, Pablo can buy 2 pair of pants and 4 shirts.
Step-by-step explanation:
A. Let x be the number of pairs of pants and y be the number of shirts.
We have been given that Pablo wants to purchase 6 additional clothing pieces for his wardrobe. We can represent this information as:
We are also told that each pair of pants costs $20 and each shirt costs $15. So the cost of x pairs of pants will be 20x and cost of y shirts will be 15y.
As Pablo wants to spend $100 on clothing, so we can represent this information as:
Therefore, the system of equation representing the given situation will be:
B. To find if Pablo can buy 2 pair of pants and 4 shirts we will substitute x=2 and y=4 in our both equations.
We can see that x=2 and y=4 satisfies our both equation, therefore, Pablo can buy 2 pair of pants and 4 shirts.
Answer:
C. 16√3π in.
Step-by-step explanation:
Circumference of a circle = 2πr where
r is the radius of the circle.
Given the area of one of the smaller circle to be 48π in², we can get the radius of one of the smaller circle.
If A = πr²
48π = πr²
r² = 48
r = √48 in
The radius of one of the smaller circle is √48.
To get the circumference of the larger circle, we need the radius of the larger circle. The radius R of the larger circle will be equivalent to the diameter (2r) of one of the smaller circle.
R = 2r
R = 2√48 inches
Since C = 2πR
C = 2π(2√48)
C = 4√48π in
C = 4(√16×3)π in
C = 4(4√3)π in
C = 16√3π in
Thw circumference of the larger circle is 16√3π in.
Answer: I assume the radius is 1/2 the base of 6 in.
r = 3 ft
h = 10 ft
s = 10.4403 ft
V = 94.2478 ft³
L = 98.3976 ft²
B = 28.2743 ft²
A = 126.672 ft²
r = radius
h = height
s = slant height
V = volume
L = lateral surface area
<span>B = base surface area </span>
A = total surface area
π<span> = pi = 3.14159</span>
<span>√ = square root</span>
The answer to your question is b.
Solution for x^2+5x=150 equation:
<span>Simplifying
x2 + 5x = 150
Reorder the terms:
5x + x2 = 150
Solving
5x + x2 = 150
Solving for variable 'x'.
Reorder the terms:
-150 + 5x + x2 = 150 + -150
Combine like terms: 150 + -150 = 0
-150 + 5x + x2 = 0
Factor a trinomial.
(-15 + -1x)(10 + -1x) = 0
Subproblem 1Set the factor '(-15 + -1x)' equal to zero and attempt to solve:
Simplifying
-15 + -1x = 0
Solving
-15 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '15' to each side of the equation.
-15 + 15 + -1x = 0 + 15
Combine like terms: -15 + 15 = 0
0 + -1x = 0 + 15
-1x = 0 + 15
Combine like terms: 0 + 15 = 15
-1x = 15
Divide each side by '-1'.
x = -15
Simplifying
x = -15
Subproblem 2Set the factor '(10 + -1x)' equal to zero and attempt to solve:
Simplifying
10 + -1x = 0
Solving
10 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-10' to each side of the equation.
10 + -10 + -1x = 0 + -10
Combine like terms: 10 + -10 = 0
0 + -1x = 0 + -10
-1x = 0 + -10
Combine like terms: 0 + -10 = -10
-1x = -10
Divide each side by '-1'.
x = 10
Simplifying
x = 10Solutionx = {-15, 10}</span>
