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Neporo4naja [7]
3 years ago
9

David added 2 and 3 using the number line tool

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

C

Step-by-step explanation:

He moved right 3 for negative 3

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What mixed number is located at the point on the number line?
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I don't exactly understand your question, mate.
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Solve for the missing side “b” and simplify your answer.
tensa zangetsu [6.8K]

Answer: sqrt(62)

Step-by-step explanation:

8 0
3 years ago
A rectangle is measured 6.5 cm by 7.8 cm .
mote1985 [20]

Answer:

3.24%

Step-by-step explanation:

Percentage error =[ (|calculated value  - actual value) / actual value] x 100

calculated area = length x width

6.5 x 7.8 = 50.7

[(|50.7 - 52.4|] / 52.4] x 100 = 3,24

7 0
3 years ago
Find a1 if Sn = 89,800, r = 3.4, and n = 10. Round to the nearest hundredth if necessary.
xxMikexx [17]

Answer:

a_1=1.04

Step-by-step explanation:

We have a geometric  sequence with:

Sn = 89,800, r = 3.4, and n = 10

Where

Sn is the sum of the sequence

r is the common ratio

a_1 is the first term in the sequence

n is the number of terms in the sequence

The formula to calculate the sum of a finite geometric sequence is:

S_n=\frac{a_1(1-r^n)}{1-r}

Then:

89,800=\frac{a_1(1-(3.4)^{10})}{1-3.4}

Now we solve for a_1

89,800(1-3.4)=a_1(1-(3.4)^{10})

a_1=\frac{89,800(1-3.4)}{1-(3.4)^{10}}\\\\a_1=1.04

4 0
4 years ago
(5x^5) - (80x^3)<br> factoring
elena55 [62]

Answer:

Factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

Step-by-step explanation:

We need to factor the term (5x^5) - (80x^3)

First we can see that 5x^3 is common in both terms

So, taking 5x^3 common:

(5x^5) - (80x^3)\\=5x^3(x^2-16)

We can write x^2-16 as (x)^2-(4)^2

=5x^3((x)^2-(4)^2)

Now we can solve (x)^2-(4)^2 using the formula: a^2-b^2=(a+b)(a-b)

We can write:

=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)

So, factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

4 0
3 years ago
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