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Neporo4naja [7]

3 years ago

9

David added 2 and 3 using the number line tool

1 answer:

FromTheMoon [43]3 years ago

6 0

Answer:

C

Step-by-step explanation:

He moved right 3 for negative 3

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What mixed number is located at the point on the number line?

Sholpan [36]

I don't exactly understand your question, mate.

4 0

3 years ago

Read 2 more answers

Solve for the missing side “b” and simplify your answer.

tensa zangetsu [6.8K]

Answer: sqrt(62)

Step-by-step explanation:

8 0

3 years ago

A rectangle is measured 6.5 cm by 7.8 cm .

mote1985 [20]

Answer:

3.24%

Step-by-step explanation:

Percentage error =[ (|calculated value - actual value) / actual value] x 100

calculated area = length x width

6.5 x 7.8 = 50.7

[(|50.7 - 52.4|] / 52.4] x 100 = 3,24

7 0

3 years ago

Find a1 if Sn = 89,800, r = 3.4, and n = 10. Round to the nearest hundredth if necessary.

xxMikexx [17]

Answer:

$a_1=1.04$

Step-by-step explanation:

We have a geometric sequence with:

$Sn = 89,800$ , $r = 3.4$ , and $n = 10$

Where

Sn is the sum of the sequence

r is the common ratio

$a_1$ is the first term in the sequence

n is the number of terms in the sequence

The formula to calculate the sum of a finite geometric sequence is:

$S_n=\frac{a_1(1-r^n)}{1-r}$

Then:

$89,800=\frac{a_1(1-(3.4)^{10})}{1-3.4}$

Now we solve for $a_1$

$89,800(1-3.4)=a_1(1-(3.4)^{10})$

$a_1=\frac{89,800(1-3.4)}{1-(3.4)^{10}}\\\\a_1=1.04$

4 0

4 years ago

(5x^5) - (80x^3)<br> factoring

elena55 [62]

Answer:

Factoring the term $(5x^5) - (80x^3)$ we get $\mathbf{5x^3(x-4)(x+4)}$

Step-by-step explanation:

We need to factor the term $(5x^5) - (80x^3)$

First we can see that $5x^3$ is common in both terms

So, taking $5x^3$ common:

$(5x^5) - (80x^3)\\=5x^3(x^2-16)$

We can write $x^2-16$ as $(x)^2-(4)^2$

$=5x^3((x)^2-(4)^2)$

Now we can solve $(x)^2-(4)^2$ using the formula: $a^2-b^2=(a+b)(a-b)$

We can write:

$=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)$

So, factoring the term $(5x^5) - (80x^3)$ we get $\mathbf{5x^3(x-4)(x+4)}$

4 0

3 years ago