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4 years ago

What is the square root of 149 rounded to the nearest tenth?

2 answers:

6 0

Hello there,
The square root of 149 is <span>12.2065556157
Thus rounding that number to the nearest tenth is equals to 12.2

Hope this helps :))

~Top
</span>

Ad libitum [116K]4 years ago

3 0

Rounded to the nearest tenth, the square root of 149 is 12.2.

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The graph shows the function f(x) = 2*<br> What is the value of xwhen f(x) = 8?

soldi70 [24.7K]

Answer:

x=3

Step-by-step explanation:

f(x) = 2^x

Let f(x) =8

8 = 2^x

Rewriting 8 as 2^3

2^3 = 2^x

The bases are the same so the exponents are the same

3=x

3 0

3 years ago

Read 2 more answers

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago

I need help I cant figure them out and they are due in 2 hours.

Vikki [24]

Answer: something

Step-by-step explanation:

Cant see the attatchment

4 0

3 years ago

Here's the rest of my points for anyone who wants them :)

kramer

Answer:

Step-by-step explanation:

line in the middle is an angle bisector

14/6 = 21 / 3x - 12

first, cross multiply

14 (3x - 12) = 6*21

Remove the brackets

42x - 168 = 126

Add 168 to both sides

42x = 168 + 126

Combine

42x = 294

Divide by 42

x = 294/42

x = 7

chegg

brainly.com/question/16979551?utm_source=android&utm_medium=share&utm_campaign=question

3 0

2 years ago

Read 2 more answers

The table shows a linear function. Which equation represents the function?

4vir4ik [10]

Question is not complete and so I have attached the complete question.

Answer:

C: f(x) = -½x + 4

Step-by-step explanation:

Using slope formula between 2 points, we know that;

slope; m = (y2 - y1)/(x2 - x1)

Let's consider 2 points from the table;

(0, 4) and (-4, 6)

Thus;

m = (6 - 4)/(-4 - 0)

m = 2/-4

m = -½

Now using slope intercept form equation which is y - y1 = m(x - x1), we can find the equation of the function by picking on point say (0, 4).

Thus;

y - 4 = -½(x - 0)

y - 4 = -½x

y = -½x + 4

Thus;

f(x) = -½x + 4

8 0

3 years ago