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Artist 52 [7]
2 years ago
9

1. For each of the molecules below, determine the electron geometry, molecule geometry, and bond

Chemistry
1 answer:
Alexxx [7]2 years ago
8 0

Answer:

CCl4- tetrahedral bond angle 109°

PF3 - trigonal pyramidal bond angles less than 109°

OF2- Bent with bond angle much less than 109°

I3 - linear with bond angles = 180°

A molecule with two double bonds and no lone pairs - linear molecule with bond angle =180°

Explanation:

Valence shell electron-pair repulsion theory (VSEPR theory) helps us to predict the molecular shape, including bond angles around a central atom, of a molecule by examination of the number of bonds and lone electron pairs in its Lewis structure. The VSEPR model assumes that electron pairs in the valence shell of a central atom will adopt an arrangement which tends to minimize repulsions between these electron pairs by maximizing the distance between them. The electrons in the valence shell of a central atom are either bonding pairs of electrons, located primarily between bonded atoms, or lone pairs. The electrostatic repulsion of these electrons is reduced when the various regions of high electron density assume positions as far apart from each other as possible.

Lone pairs and multiple bonds are known to cause more repulsion than single bonds and bond pairs. Hence the presence of lone pairs or multiple bonds tend to distort the molecular geometry geometry away from that predicted on the basis of VSEPR theory. For instance CCl4 is tetrahedral with no lone pair and four regions of electron density around the central atom. This is the expected geometry. However OF2 also has four regions of electron density but has a bent structure. The molecule has four regions of electron density but two of them are lone pairs causing more repulsion. Hence the observed bond angle is less than 109°.

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In acid solution, water can add to the double bond of 2‑butenedioic acid to form 2‑hydroxysuccinic acid.
Art [367]

Answer:

Explanation:

The stereochemical structures of the two compounds of the fumarase-catalyzed reaction are in the attachment below. The reaction been referred to is illustrated in the equation below

HOOCCH=CHCOOH + H₂O ==> HOOCCH₂CH(OH)COOH

The compounds attached are trans-2-butenedioate (which is one of the reactants) and (s)-2-hydroxysuccinate (which is the product formed)

Note that stereoisomers are isomers that differ in spatial orientation, thus there are other isomers that could contain the same atoms and have slightly but different spatial orientation such as cis-2-butenedioate and (r)-2-hydroxysuccinate

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2 years ago
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Leno4ka [110]
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Plz help me with seven eight and nine
Nookie1986 [14]
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3 years ago
How many electrons in an atom can share the quantum numbers n = 4 and l = 3?
o-na [289]

Answer:

\boxed{\text{14}}

Explanation:

If l = 3, the electrons are in an f subshell.

The number of orbitals with a quantum number l is 2l + 1, so there

are 2×3 + 1 = 7 f orbitals.

Each orbital can hold two electrons, so the f subshell can hold 14 electrons.

\boxed{\textbf{14 electrons}} \text{ can share the quantum numbers n = 4 and l = 3.}

3 0
3 years ago
The specific rotation of (S)-2-butanol is +13.5. If 0.119 g of its enantiomer is dissolved in 10.0 mL of ethanol and
larisa86 [58]

Answer:

+15.8°

Explanation:

The formula for the observed rotation (α) of an optically active sample is

α = [α]<em>lc </em>

where

<em>l</em> = the cell path length in decimetres

<em>c</em> = the concentration in units of g/100 mL

[α] = the specific rotation in degrees  

1. Convert the concentration to units of g/100 mL

c = \frac{\text{0.119 g}}{\text{10.0 mL}} \times \frac{10 }{10 } =\frac{\text{1.19 g}}{\text{100 mL}}

2. Calculate the observed rotation

\alpha = (+13.3 ^{\circ}) \times 1.19 \times 1 = +15.8^{\circ}

7 0
3 years ago
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