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charle [14.2K]
2 years ago
11

What is the percent enantiomeric excess (ee) of a mixture that has 86% of one enantiomer and 14% of the other

Chemistry
1 answer:
solniwko [45]2 years ago
6 0

Answer:

86% - 14% = 72%

Explanation:

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Which term can be used to describe the process in the reaction below? 2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)
Setler79 [48]

Answer:

Decomposition

Explanation:

If we look at the process;

2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)

We can see that NaHCO3 was broken down into Na2CO3, H2O and CO2.

The breakdown of one compound to yield other chemical compounds is known as decomposition.

Hence the NaHCO3 was decomposed in the process above.

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2 years ago
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Answer:

2) Add a solution of NaBr

Explanation:

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PbBr₂ is slightly soluble in ammonia, and it reacts with NaOH to produce Pb(OH)₂ and NaBr

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4 0
2 years ago
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Radda [10]

Answer:

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Explanation:

You need to compare the number of coefficient of the reaction product to find how much water produced. The reaction formula will produce 6 carbon dioxide(CO2) and 6 water (H2O).

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The molar mass of water is 18g/mol, so the calculation of moles to mass will be: 0.92 moles * (18g/mol)= 16.56g.

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