Answer:
19.K, potassium
Explanation:
it has all properties of metals
Answer:
ΔH = 2.68kJ/mol
Explanation:
The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:
q = m*S*ΔT
<em>Where q is heat of reaction in J,</em>
<em>m is the mass of the solution in g,</em>
<em>S is specific heat of the solution = 4.184J/g°C</em>
<em>ΔT is change in temperature = 11.21°C</em>
The mass of the solution is obtained from the volume and the density as follows:
150.0mL * (1.20g/mL) = 180.0g
Replacing:
q = 180.0g*4.184J/g°C*11.21°C
q = 8442J
q = 8.44kJ when 3.15 moles of the solid react.
The ΔH of the reaction is:
8.44kJ/3.15 mol
= 2.68kJ/mol
Answer: here is your answer
Explanation: You are visiting your Grandmother and notice that she is eating a balanced diet, taking vitamins, getting the proper amount of sleep and is not overweight. Despite her healthy lifestyle, she appears run down and tired. You realize that it's due to her lack of physical activity. Write a convincing letter to your grandma explaining the benefits of participating in regular physical activity.
Answer:
The new volume is 1.62 L
Explanation:
Boyle's law says:
"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." It is expressed mathematically as:
Pressure * Volume = constant
o P * V = k
Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. So this law indicates that the quotient between pressure and temperature is constant.
Gay-Lussac's law can be expressed mathematically as follows:

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law.

Having an initial state 1 and a final state 2 it is possible to say that:

Standard temperature and pressure (STP) indicate pressure conditions P = 1 atm and temperature T = 0 ° C = 273 ° K. Then:
- P1= 1 atm
- V1= 1.2 L
- T1= 273 °K
- P2= 0.80 atm
- V2= ?
- T2= 21°C= 294 °K
Replacing:

Solving:

V2= 1.62 L
<u><em>The new volume is 1.62 L</em></u>
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