For the n = 3 electron shell, which of the following quantum numbers are valid? Check all that apply.
2 answers:
Answer:
The valid quantum numbers are l=0, l=-2 and l= 2.
Explanation:
Given that,
n = 3 electron shell
Suppose, the valid quantum numbers are
l = 3
m = 3
l = 0
m = –2
l = –1
m = 2
We know that,
The value of n = 3
Principle quantum number :
Then the principal quantum number is 3. Which is shows the M shell.
So, n = 3
Azimuthal quantum number :
The azimuthal quantum number is l.
Magnetic quantum number :
The magnetic quantum number is
Hence, The valid quantum numbers are l=0, l=-2 and l= 2.
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Option B: high pressure and low temperature
A gas is more soluble under high pressure and low temperature conditions.
On increasing temperature of a gas, its kinetic energy increases. The increase in kinetic energy increases the motion of particles of gas this causes most of the gaseous particles to escape from the gas phase. Thus, less particles are available to dissolve in liquid and solubility decreases.
The effect of pressure on solubility of gas can be explained with the help of Henry's law. According to the law, at constant temperature, solubility of gas and partial pressure of gas are related to each other as follows:
Here, p is the partial pressure of the gas, is Henry's law constant, and
c is the concentrate of the gas.
According to above relation, concentration of gas decreases on decreasing partial pressure. Thus, on increasing pressure, concentration of gas increases this increases the solubility of gas in liquid.
Therefore, solubility of gas is greatest at high pressure and low temperature.