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lord [1]
2 years ago
11

In each pair, choose the larger of the indicated quantities or state that the samples are equal:

Chemistry
1 answer:
sammy [17]2 years ago
7 0

3.3 g of SO₂  is a larger quantity in moles.

<h3>What is moles?</h3>

Mole, also spelled mol, in chemistry, a standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles.

The mole designates an extremely large number of units, 6.02214076 × 10^{23}. The General Conference on Weights and Measures defined the mole as this number for the International System of Units (SI) effective from May 20, 2019. The mole was previously defined as the number of atoms determined experimentally to be found in 12 grams of carbon-12.

The number of units in a mole also bears the name Avogadro’s number, or Avogadro’s constant, in honour of the Italian physicist Amedeo Avogadro (1776–1856). Avogadro proposed that equal volumes of gases under the same conditions contain the same number of molecules, a hypothesis that proved useful in determining atomic and molecular weights and which led to the concept of the mole.

Learn more about mole

brainly.com/question/1427235

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Group 7a of the periodic table contains the most or least reactive elements
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1. Calculate the molar mass of sucrose (C12 H11 O22)?
ohaa [14]

Answer:

=342g

Explanation:

atomic mass of C = 12g

atomic mass of H =  1g

atomic mass of O = 16g

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    C12 H22 O11

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4 0
2 years ago
Air at 30.0% relative humidity is cooled isobarically at 1 atm absolute from 75.0°C to 35.0°C. a. Estimate the dew point and the
Dvinal [7]

Answer:

a. Dew point: 48.7°C. Degrees of superheat 26.3°C

b. 3.33mol/m^3

c. P=3.34atm

Explanation:

a. Based on the psychometric chart of air, the specific volume of air at the given conditions is:

v =\frac{RT}{PM} =\frac{0.082\frac{atm*L}{mol*K}*348.15K}{1atm*28.97g/mol} *\frac{1m^3}{1000L}*\frac{1000g}{1kg}  =0.98544m^3/kg

The dew point at the specific volume and the 30%-humidity has a value of 48.7°C, it means that there are 75°C-48.7°C=26.3°C of superheat.

b. At 75°C the molar fraction of water is 11580Pa/101625Pa=0.114 moles per cubic meter of feed gas are:

\frac{n}{V}=y_{H_2O}\frac{P}{RT}=0.114\frac{1atm}{0.082\frac{atm*L}{mol*K}*348.15K} }*\frac{1000L}{1m^3}    \\\frac{n}{V}=4mol/m^3

Once the 35°C are reached, the mole fraction of water is 1688Pa/101325Pa=0.017 and remaining moles per cubic meter of feed gas are:

\frac{n}{V}=y_{H_2O}\frac{P}{RT}=0.017\frac{1atm}{0.082\frac{atm*L}{mol*K}*308.15K} }*\frac{1000L}{1m^3}    \\\frac{n}{V}=0.673mol/m^3

So the condensed moles per cubic meter of feed gas are:

4mol/m^3-0.673mol/m^3=3.33mol/m^3

c. Considering the Raoult's law, one computes the pressure as follows:

P=\frac{P^{sat}_{H_2O}}{y_{H_2O}}

At 75°C and 30%-humidity, the saturation water vapor pressure has a value of 38599Pa, thus:

P=\frac{38599Pa}{0.114}*\frac{1atm}{101325Pa} \\P=3.34atm

Best regards.

6 0
3 years ago
How do I name this chemistry question
levacccp [35]
You find out what they are for example water,oxygen etc. you know wat i mean

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