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vichka [17]
3 years ago
14

You are putting a rectangular hot tub on your back porch. It is 6 feet long, 5 feet wide, and 3 feet deep

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0

Answer:

a) 90 cubic foot

b) 90 cubic foot = 667.62 gallons

c) $3.3381

Step-by-step explanation:

a)

volume of rectangular hot tub

= 6*5*3

= 90 cubic foot

b)

1 cubic foot = 7.418 gallons

90 * 1 cubic foot = 90 * 7.418 gallons

90 cubic foot = 667.62 gallons

c)

$5 = 1000 gallons

($5 / 1000) = (1000 / 1000) gallons

.005 * 667.62 = 1 * 667.62 gallons

$3.3381 = 667.62 gallons

Lyrx [107]3 years ago
5 0

Answer:

Step-by-step explanation:

The formula for determining the volume of a cuboid is expressed as

Volume = L × W × H

The rectangular hot tub is 6 feet long, 5 feet wide, and 3 feet deep. This means that

a) The number of cubic feet that the hot tub hold if it is completely full would be

5 × 6 × 3 = 90 ft^3

b) if 1 cubic foot = 7.418 gallons, then it means the number of gallons that it can hold would be

90 × 7.418 = 667.62 gallons

c) if water costs $5 per 1000 gallons, then the cost of filling the hot tub would be

(5 × 667.62)/1000 = 3338.1/1000

= $3.3381

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Step-by-step explanation:

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PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of
Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

8 0
3 years ago
Read 2 more answers
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