All categories

3 years ago

What is 2/3 - 8/15 ?

Mathematics

1 answer:

suter [353]3 years ago

8 0

Answer:

2/15

Step-by-step explanation:

2/3 - 8/15

Get a common denominator

2/3 *5/5 = 10/15

10/15 - 8/15

2/15

You might be interested in

3/7×2 5/6= <br> i just dont know what the answer is like my brain is really bad in the mornings

cestrela7 [59]

Answer:

Hello :)

Step-by-step explanation:

1 3/14

3/7*2 5/6= 1 3/14

8 0

3 years ago

Read 2 more answers

What principal invested at 8% compounded continuously for 4 years will yield $1190?

zhuklara [117]

For continuously compounded interest:

Amount = Principle * e^(rate * time)

A rate of 8% converted to a decimal value: r=0.08
With time t=4
and amount 1190

Plug all these values in,

1190 = Principle * e^(0.08 * 4)

And use your calculator to solve for the principle.
Maybe we'll call it P to make things easier.

1190 = P * e^(0.08 * 4)
1190 = P * 1.377

The principle is being multiplied by this 1.377,
divide by 1.377 to undo the multiplication.

864.11735 = P

7 0

3 years ago

Combine like terms. <br> 8x2 + 2(x2 − 1) =

podryga [215]

Answer:

Step-by-step explanation:

8x² + 2(x²-1) = 8x² + 2*x² - 2*1

= 8x² + 2x² -2

= 10x² -2

Like terms: 8x² , 2x²

6 0

4 years ago

Read 2 more answers

A scuba diver at a depth of -12ft(12 ft below sea level),dives down to a coral reef that is 3.5 times the divers original depth.

svet-max [94.6K]

-42ft below sea level

3 0

4 years ago

Select the correct answer from each drop-down menu.

podryga [215]

Answer with explanation:

$\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}$

Average Height of tallest Building in San Francisco

$=\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8$

Average Height of tallest Building in Los Angeles

$=\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9$

→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco

=233.9-197.8

=36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

|260-197.8|=62.2

|237-197.8|=39.2

|212-197.8|=14.2

|197 -197.8|= 0.8

|184 -197.8|=13.8

|183-197.8|=14.8

|183-197.8|= 14.8

|175-197.8|=22.8

|174-197.8|=23.8

|173 -197.8|=24.8

Average of these numbers

$=\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12$

Mean absolute deviation=23.12

5 0

3 years ago