1 puzzle time how did the man at the seafood restaurant cut his mouth answers

Explain the relationships between five members of a food web. Include at least one producer and one high-level consumer

kolezko [41]

Answer:

the sun shines on earth, which through photosynthesis in a humble blade of grass turns into food and energy for the grass. now a small mouse hops along, stomach growling. it eats our blade of grass now itself getting energy. the naive, full mouse hops through the field before it squeaks in horror. a snake slinks towards it. the mouse is too slow. and the mouse breathes his last breath. the snake swallows it whole. stomach content now digesting its new energy sleeps. before it has the chance to react a hawk snatches it up in her claws. killing it she eats. this snake is poisonous, the next time our hawk flies, she stumbles, then falls. vanquished by poison her lifeless body lies in the dirt. her nutrients go into the soil, thanks to decomposers like worms. her nutrients help new grass blades grow, and the cycle continues.

I hope this helps u!

Pls give brainliest(had 40 down to 2 for no reason and worked long) and a thx ;)

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5 0

3 years ago

In a(n) _________________________________, one of the blood vessels in the brain ruptures or breaks open and blood enters the br

lianna [129]

Answer:

Hemorrhagic Cerebrovascular accident (CVA) also called stroke

Also an aneurysm can rupture and cause same effect.

3 0

3 years ago

What does sulfur dioxide and hydrogen sulfide form in the atmosphere that is bad

egoroff_w [7]

Answer:

At high temperatures or in the presence of catalysts, sulfur dioxide reacts with hydrogen sulfide to form elemental sulfur and water. This reaction is exploited in the Claus process, an important industrial method to dispose of hydrogen sulfide.

(credits to the owners of this answer :)

5 0

3 years ago

Increased urination brought on by drinking too mugh ethyl alcohol is due to

inn [45]

Answer:

The correct answer is option b, that is, inhibition of vasopressin.

Explanation:

Vasopressin also called ADH or anti-diuretic hormone results in the resorption of water by the collecting duct and the distal convoluted tubule of the nephron, and thus, minimizes the reduction of water via urine. Consuming ethyl alcohol results in the prevention of the secretion of ADH that results in frequent urination.

7 0

3 years ago

4) A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality)

docker41 [41]

Answer and Explanation:

A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality).

The F1 females are testcrossed, producing these offspring: groucho 518 rough 471 groucho, rough 6 wild-type 5 1000 a) What is the linkage distance between the two genes? B) Plot the genes on a map c) If the genes were unlinked and the F1 females were mated with the F1 males, what would be the offspring in the F2 generation?

1st cross:

Parental) grogro ro+ro+ x gro+gro+ roro

F1) gro+gro ro+ro

2nd cross:

Parental) gro+gro ro+ro x grogro roro

Gametes) gro+ro+ gro ro

gro+ro gro ro

gro ro+ gro ro

gro ro gro ro

Punnet square)

gro+ro+ gro+ro gro ro+ gro ro

gro ro gro+gro ro+ro gro+gro roro grogro ro+ro grogro roro

F2)

0.518 grogro ro+ro (518 individuals)

0.471 gro+gro roro (471 individuals)

0.006 grogro roro (6 individuals)

0.005 gro+gro ro+ro (5 individuals)

Total number of individuals 1000

Note: These frequencies were calculated dividing the number of individuals belonging to each genotype by the total number of individuals in the F2.

To know if two genes are linked, we must observe the progeny distribution. If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent.

In the exposed example we might verify which are the recombinant gametes produced by the F1 di-hybrid, and we can recognize them by looking at the phenotypes with lower frequencies in the progeny.

By performing this cross we know that the phenotypes with lower frequencies in the progeny are groucho, rough and wild-type. So the recombinant gametes are gro+ro+ and gro ro, while the parental gametes are gro+ro and gro ro+.

So, the genotype, in linked gene format, of the double heterozygote individual in the F1 is gro+ro/gro ro+.

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).

The map unit is the distance between the pair of genes for which one of every 100 meiotic products results in a recombinant product.

The recombination frequency is:

P = Recombinant number / Total of individuals

P = 6 + 5 / 1000

P = 11 / 1000

P = 0.011

The genetic distance between genes, is 0.011 x 100= 1.1 MU.

Genetic Linkage Map:

Parental Phenotypes)

-----gro+------ro---- -----gro------ro+----

----- gro ------ro---- ---- gro------ ro ----

Recombinant phenotypes)

-----gro+------ro+---- -----gro------ro----

----- gro ------ ro---- -----gro------ro----

If the genes were unlinked and the F1 females were mated with the F1 males, the offspring in the F2 generation would have been

4/16 = 1/4 gro+gro ro+ro

4/16 = 1/4 gro+gro roro

4/16 = 1/4 grogro ro+ro

4/16 = 1/4 grogro roro

Their phenotypic frequencies would be 1:1:1:1 related.

7 0

3 years ago