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Vilka [71]
3 years ago
7

What is conjugate base for h20?

Chemistry
1 answer:
dexar [7]3 years ago
8 0

Answer:

OH-

Explanation:

H2O can act as base or acid.

When H2O acts as a base the conjugate acid is H3O+

When H2O acts as an acid the conjugate base is OH-

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15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams
sveticcg [70]

Answer:

\boxed {\tt A. \ d=0.85 \ g/mL}

Explanation:

Density is found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

m= 12.7 \ g\\v= 15 \ mL

Substitute the values into the formula.

d=\frac{12.7 \ g}{ 15 mL}

Divide.

d=0.846666667 \ g/mL

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

d \approx 0.85 \ g/mL

The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

4 0
3 years ago
Lab activity - Law of Conservation of Mass with vinegar and baking soda.
lesya [120]

Answer: I BIG DUMB

Explanation:

7 0
3 years ago
Is calcium carbonate a compound element or mixture?
uysha [10]

It's a compound because it's formed from an ionic bond between calcium and carbon so it's an ionic compound

7 0
4 years ago
The table below shows the density of a sample of a mystery liquid you tested in the lab. Can you infer the identity of the subst
Mashutka [201]

Answer:

A. Yes, the substance must be water.

Explanation:

The density of a substance is unique to it. Density is defined the as the amount of substance contained per volume.

One of the ways of identifying a substance is to determine its density. Every matter is known to have their own specific densities. This makes them different from other substances. The density of gold is unique to it and it differs from that of silver.

In fact, water has density of 1.00gcm⁻³. Experimental errors and some little factors must have altered our expected figure. This a case of precision and accuracy in the experiment.

7 0
3 years ago
A 3.0 l container holds a sample of hydrogen gas at 300 k and 100 kpa. if the pressure increases to 400 kpa and the volume remai
Dahasolnce [82]
    The  temperature will  be  1200K   if  the volume remained   constant

      calculation
 This is calculated  using   gay lussac  law  formula,  that is P1/ T1=P2/T2  since the   volume is constant
P1 =  100 Kpa
T1=  300 K
P2=  400 Kpa
T2=?

by  making  T2   the subject of the formula  T2 =( P2 xT1)/P1

T2  is therefore = (400 KPa  x 300 K)  / 100 Kpa = 1200 K
4 0
3 years ago
Read 2 more answers
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