Next, we shall determine the mass of aluminum chloride, AICI₃ that reacted and the mass of silver chloride, AgCl produced from the balanced equation. This is illustrated below:

Molar mass of AICI₃ = 133.34 g/mol

Mass of AICI₃ from the balanced equation = 1 × 133.34 = 133.34 g

Molar mass of AgCl = 143.32 g/mol

Mass of AgCl from the balanced equation = 3 × 143.32 = <em>429.96 g</em>

<h3>SUMMARY</h3>

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Finally, we shall determine the theoretical yield of AgCl by the reaction of 1.616 g of AICI₃ as follow:

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Therefore,

1.616 g of AICI₃ will react to produce = $\frac{1.616 * 429.96}{133.34}$ = 5.2109 g of AgCl.

Thus, the theoretical yield of silver chloride, AgCl is 5.2109 g

Learn more: brainly.com/question/24653699

3 0

2 years ago

If a flask maintained at 674 K contains 0.138 moles of NH4I(s) in equilibrium with 4.34×10-2 M NH3(g) and 9.39×10-2 M HI(g), wha

r-ruslan [8.4K]

Answer:

K = 4.07x10⁻³

Explanation:

Based on the reaction:

NH₄I(s) ⇄ NH₃(g) + HI(g)

You can define K of equilibrium as the ratio of concentrations of reactants and products, thus:

K = [NH₃] [HI] / [NH₄I]

But, as NH₄I is a solid, is not taken into account in the equilibrium, that means K expression is:

K = [NH₃] [HI]

As the concentrations in equilibrium of the gases is:

[NH₃] = 4.34x10⁻²M

[HI] = 9.39x10⁻²M

Equilibrium constant, K, is:

K = 4.34x10⁻²M * 9.39x10⁻²M

4 0

2 years ago