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ryzh [129]
4 years ago
5

Can someone please help me w/ this geometry question? image attached.

Mathematics
1 answer:
serg [7]4 years ago
4 0

Answer:

The answer is A: Reflexsive property of congruence

Step-by-step explanation:


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PLZZ HELP!!! ⚠️⚠️ ATTACHED AND NEEDS DONE ASAP!
Nataly [62]

Step-by-step explanation:

change the unit

50 km per 1 hour

50 km/h = 50,000 m/ 3600 s = 13.8 m/s

the lorry speed is 13.5 m/s or 0.3 m slower than the limit

8 0
3 years ago
Need help please very confuzzled
SVEN [57.7K]
I'm not too sure either.

5(5) + 3(5) = 40 and

5(2) + 3 (10) = 40

If you can't think of anything maybe that'll help
7 0
3 years ago
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Nigel tried to solve an equation step by step
kaheart [24]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
Number A3 part 2 show that x is sufficiently small for x⁴
Dahasolnce [82]
Lopo d’oro es qua la
4 0
3 years ago
A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s
ANTONII [103]
<h2>Hello!</h2>

The answer is:

The ball will hit the ground after t=2.47s

<h2>Why?</h2>

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula.  We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

We are given the function:

h=-5t^{2}-3t+38

Where,

a=-5\\b=-3\\c=38

Then, substituting it into the quadratic equation, we have:

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s

Since negative time does not exists, the ball will hit the ground after:

t=2.473s=2.47s

Have a nice day!

4 0
3 years ago
Read 2 more answers
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