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Stells [14]
3 years ago
12

Find the volume of a sphere with a great circle that has a circumference of 42 πft

Mathematics
1 answer:
stellarik [79]3 years ago
3 0

Answer:

43.982297

Step-by-step explanation:

42xπ =131.946891

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Jason took a taxi from his home to the airport. <br> the taxi driver charged an initial fee of $12
viva [34]

Answer:

really explain the question more

Step-by-step explanation:

3 0
3 years ago
James sees a truck at the dealership for $28,000
Lera25 [3.4K]

Answer:

The correct answer is C. $28,200.

Step-by-step explanation:

Given that James saw a truck at the dealership for $ 28,000 base price, $ 1,300 premium interior, $ 1,200 navigation touch-screen, and $ 1,700 smart traffic sensors, if his current vehicle is worth $ 5,000 and he's offered a 60% trade-in rate, to determine what is the total cost of the car after the $ 1,000 destination fee, the following calculation must be made:

28,000 + 1,300 + 1,200 + 1,700 - (5,000 x 60/100) = X

32,200 - (5,000 x 0.6) = X

32,200 - 3,000 = X

29,200 = X

29,200 - 1,000 = 28,200

Therefore, the total cost of the car after the $ 1,000 destination fee is $ 28,200.

3 0
3 years ago
Help will mark Brainly
o-na [289]

Answer:

V ≈ 8.67x10^7 ft^3

Step-by-step explanation:

We know that the volume of a pyramid is V= (lwh)/3

Since it is a square pyramid, it means that the length and the width are the same:

Length=755.9 feet

Width=755.9 feet

Height=455.4 feet

So, the volume is :

V = [(755.9)(755.9)(455.4)]/3

V = 86736214.158 ft^3

V ≈ 8.67x10^7 ft^3

Hope this helps!

Mark brainliest if u think I helped! Would really appreciate!

6 0
3 years ago
Help me out !?!??!?!l
Vlada [557]

Answer:67 is correct D

Step-by-step explanation:use parallel, so 71+x=180-42 x=67 67+71=138, 67= to your answer

4 0
2 years ago
In matrix theory, many of the familiar properties of the real number system are not valid. If a and b are real numbers, then ab
kozerog [31]

Answer:

B=\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right]

Step-by-step explanation:

Let's do the multiplication AB.

If A=\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right]

then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.

the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.

the second row of A is= (0 0) by any colum of B is equal to zero too.

So we have found an example that works!

7 0
3 years ago
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