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Mrrafil [7]
3 years ago
7

what are the coordinates of a point on the unit circle if the angle formed by the positive x- axis and the radius is 45°??

Mathematics
1 answer:
Delvig [45]3 years ago
4 0
On the unit circle, the radius is 1 and the trigonometric ratios are:

sin(angle( = y-coordinate / radius = y-coordinate / 1 = y-coordinate = y

cos(angle) = x-coordinate / radius = x-coordinate / 1 = x

Then:

y = sin(angle) = sin(45°) = √2 / 2

x = cos (angle) = cos (45°) = √2 / 2

=> Answer: (√2 / 2 , √2 / 2), which is the option A)
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Factor the four term polynomial by grouping.<br>10x^3-15x^2+6x-9​
goldfiish [28.3K]

Answer:

(5x²  + 3) (2x-3)

Step-by-step explanation:

10x³ - 15x² + 6x - 9   (rearrange)

10x³+ 6x - 15x²  - 9  (group using parentheses)

(10x³+ 6x) - (15x²  + 9)  (factor out 2x from first term and 3 from second term)

2x (5x²+ 3) - 3(5x²  + 3)   (factor out (5x²+3) )

(5x²  + 3) (2x-3)  (answer)

5 0
3 years ago
Which of the following is a rational number?
Lunna [17]
The correct answer is B
6 0
2 years ago
Complete the factorization.
lyudmila [28]
If you would like to complete the factorization, you can do this using the following steps:

<span>4p^2 + 36p + 81 = (2p + 9) * (2p + 9) = (2p + 9)^2
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6 0
3 years ago
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
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