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bonufazy [111]
4 years ago
8

(blank)a0 is undeniably accepted by scientists all over the world as the primary language of science.

Physics
2 answers:
Juliette [100K]4 years ago
5 0

Answer:

English.

Explanation:

English is undeniably accepted by scientists all over the world as the primary language of science. It is a language spoken all over the world and is also the language of science because it is an official language and can be understood by almost everyone.

BlackZzzverrR [31]4 years ago
4 0

Answer:

\boxed{\mathrm{English}}

Explanation:

English is undeniably accepted by scientists all over the world as the primary language of science. The scientific methods and experiments are done by communicating and writing in English. Scientists use English to communicate and share knowledge as English is understood by people from around the world.

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The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla
Vladimir [108]

Answer

given,

Radius of sphere = 6.38 × 10⁶ m

time  = 1 day = 86400 s

\omega = \dfrac{2\pi}{T}

\omega = \dfrac{2\pi}{ 86400 }

\omega = 7.272 \times 10^{-5}\ rad/s

a) at equator

v = R_E \omega

v = 6.38 \times 10^6\times 7.272 \times 10^{-5}

v = 464 m/s

acceleration of the person

a = \omega^2R_E

a = (7.272 \times 10^{-5})^2(6.38 \times 10^6)

a = 0.03374 m/s^2

b) at a latitude of 61.0 ° north of the equator.

R = R_E cos \theta

R = 6.38 \times 10^6\times cos 61^0

R = 3.093 \times 10^6 m

v = R \omega

v = 3.093 \times 10^6 \times 7.272 \times 10^{-5}

v = 225 m/s

acceleration of the person

a = \omega^2R_E

a = (7.272 \times 10^{-5})^2(3.093 \times 10^6 )

a = 0.01635 m/s^2

4 0
3 years ago
Determine the gravitational force of attraction experienced by a two 5.00 kilogram masses separated by a distance of 2.5 meters.
drek231 [11]
The gravitational force between two objects may be calculated through the equation,
                                     F = Gm₁m₂ / d²
where G is 6.67 x 10^-11 m³/s²kg
Substituting the known values to the equation,
                        F = (6.67 x 10^-11 m³/s²kg)(5.0 kg)(5.0 kg) / (2.5 m)²
                                     F = 2.668 x 10^-10 N
4 0
3 years ago
Speed of light in a substance with refractive index of 1.70
makkiz [27]
Whats the question? ....
7 0
3 years ago
The emission line used for zinc determinations in atomic emission spectroscopy is 214 nm. If there are 9.00×1010 atoms of zinc e
KengaRu [80]

Answer:

8.4\cdot 10^{-8}J

Explanation:

The energy emitted by a single photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength of the photon

For the photons emitted by the zinc atoms,

\lambda = 214 nm = 214 \cdot 10^{-9} m

So the energy of a single photon emitted is

E=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{214\cdot 10^{-9}}=9.3\cdot 10^{-19}J

And since the number of atoms is

N=9.0\cdot 10^{10}

The total energy emitted will be

E=NE_1 = (9.0\cdot 10^{10})(9.3\cdot 10^{-19})=8.4\cdot 10^{-8}J

3 0
4 years ago
Convert 4.565mm to m
lutik1710 [3]
It will be 0.004565 m
4 0
4 years ago
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