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2 years ago

For a sample of n = 36 that has a sample variance of 1,296, what is the estimated standard error for the sample?

Physics

1 answer:

baherus [9]2 years ago

7 0

The estimated standard error for the sample is 6.

The definition of error is a mistake or the kingdom of being wrong. An instance of a blunder is when you upload 2+2 and get five. An example of a mistake is whilst a mistake leads you to come back to the incorrect collusion and you still agree with this incorrect conclusion.

The usual error of the suggestions, or simply well-known mistakes, shows how one of a kind the population suggests is possibly to be from a sample imply. It tells you ways tons the pattern suggests would range if you were to repeat a observe the usage of new samples from within an unmarried population.

Placed truly, the standard errors of the sample mean is an estimate of the way some distance the sample suggest is in all likelihood to be from the population mean, while the usual deviation of the sample is the degree to which individuals within the sample vary from the pattern mean.

Given :

Sample size, n = 36

Sample variance, s² = 1296

The estimated standard error can be obtained using the relation :

Standard Error, S. E = standard deviation / √n

Standard deviation, s = √1296 = 36

S.E = 36/√36

S.E = 36/6

S.E = 6

Hence, estimated standard error = 6

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Heating gas to create plasma can yield A) neutrons. B) elements. C) molecules. D) free electrons.

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<h2>Answer: free electrons</h2>

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That is why in this process there are always free electrons. Therefore in heating gas to create plasma can yield free electrons, and the correct option is D.

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3 years ago

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Unpolarized light of intensity I=10 falls on two successive polarizer wheels with the angle between the polarizer wheels e-60°.

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Answer:

$I=\frac{10}{4}$

Explanation:

A polarizer changes the orientation of the oscillations of a light wave.

I₀ = Intensity of unpolarized light = 10

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3 years ago

A train has a constant speed of 10 m/s around a track with a diameter of 45 m what is the centripal acceleration?

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Answer:

$a_{c}= 4.44\frac{m}{s}$

Explanation:

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$a_{c}=\frac{v^{2}}{r}$ , with v the speed, r the radius of the track that is half of the diameter (22.5 m)

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3 years ago

The impact time for a particular collision is 3.0 x 10^-3 seconds and the impulse in the collision is 0.30 newton seconds. What

BartSMP [9]

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Explanation

The Newton's second law of motion states that, the rate of change of momentum is proportional to the force producing it.

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The quantity Ft is called the impulse.

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