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3 years ago

By what percent did the price change, if… a the price was $100 and now it is $250?

Mathematics

2 answers:

elena-s [515]3 years ago

7 0

It had a 150% increase in price

100* 1.5 = 150
150+100 = 250

Naddik [55]3 years ago

4 0

Well, if we take $100 to be the 100%, and then it went up by $150, how much is $150 off of it in percentage?

$\bf \begin{array}{ccll}
\$&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
100&100\\
150&x
\end{array}\implies \cfrac{100}{150}=\cfrac{100}{x}\implies x=\cfrac{150\cdot 100}{100}$

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Find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one

ziro4ka [17]

The probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

<h3>What is the probability?</h3>

Probability is synonymous with possibility. It is concerned with the occurrence of a random event.

Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.

No of failure,n = 7

No of trials,x≥6

A binomial probability is represented as;

$\rm P(x) = nC_x p^z(1-p)^{n-r}$

Substitute the given data;

$P(x \geq 6) = 7C_6 \times 9^6 \times 91-9)^{7-6} +7C_7 (9)^7+(1-9)^{(7-7)}$

$\rm P(x \geq 6) = 0.000000343311 \\\\ P(x \geq6)=0.000343311 \%$

Hence,the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

To learn more about probability, refer to the link: brainly.com/question/795909.

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2 years ago

Brainly to whomever somehow solves for x. I WILL REPORT SCAMS AND UNHELPFUL "WHAT?" ANSWERS.

cestrela7 [59]

Answer:

$x=\frac{33}{7}$

Step-by-step explanation:

Since ED is parallel to CA, the two triangles in the figure share all 3 angles and therefore must be similar. By definition, the corresponding sides of similar polygons are in a constant proportion.

Therefore, we have:

$\frac{11}{11+x}=\frac{14}{20},\\14(11+x)=20\cdot 11,\\11+x=\frac{20\cdot 11}{14},\\x=\frac{110}{7}-11=\boxed{\frac{33}{7}}$

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3 years ago