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alexira [117]
3 years ago
5

Help me on number problem 4 please

Mathematics
2 answers:
dlinn [17]3 years ago
8 0

Let J be the number of points Jaylen scored, and T be the number of points Trevor scored. We have two pieces of information, which are enough to determine the values of the unknowns, because there are two of them (you need as many equations as unknowns).

The first thing we're told is that they scored 485 together, so you have

J+T=485

Then we know that Jaylen scored 25 points less than Trevor, which means

J = T-25

Substitute this expression for J in the first equation to get

J+T=485 \iff (T-25)+T=485 \iff 2T=510 \iff T = 255

So, now that we know that Trevor scored 255 points, we can easily calculate Jaylen's score:

J = T-25 = 255-25 = 230

vaieri [72.5K]3 years ago
7 0
Jaylen score was 242.5 and Trevor score was 217.5
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What is the value of fraction 1 over 3x3 + 5.2y when x = 3 and y = 2?
Slav-nsk [51]

Hello from MrBillDoesMath!

Answer:

1/ 91.4

Discussion:

Evaluate  1/ ( 3x^3 + 5.2y)   when x = 3, y = 2.

1/ (3 (3)^3 + 5.2(2))  =

1/ ( 3 * 27 + 10.4) =

1/ ( 81 + 10.4) =

1/ (91.4) =

.0109 (approx)

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6 0
4 years ago
4. Exercise 8.1.10 (2 points)(a) Find a recurrence relation for the number of bit strings of positive lengthnthat containthe bit
nikdorinn [45]

Answer:

T0 =0, T1=0

Step-by-step explanation:

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8 0
3 years ago
Find the distance between the points (5,-6), (-3,12)
grigory [225]

Answer:

\displaystyle d = 2\sqrt{97}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (5, -6)

Point (-3, 12)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance<em> d</em>

  1. Substitute in points [Distance Formula]:                                                       \displaystyle d = \sqrt{(-3-5)^2+(12+6)^2}
  2. [√Radical] (Parenthesis) Subtract/Add:                                                         \displaystyle d = \sqrt{(-8)^2+(18)^2}
  3. [√Radical] Evaluate Exponents:                                                                    \displaystyle d = \sqrt{64+324}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{388}
  5. [√Radical] Simplify:                                                                                     \displaystyle d = 2\sqrt{97}
8 0
3 years ago
Help me, please?<br> trust me I need it.
mr_godi [17]

Answer: ∠MON = 15°

Step-by-step explanation:

∠LON = ∠LOM + ∠MON

(9x + 44) + (6x+3) = 77

9x + 6x + 44 + 3 = 77

15x + 47 = 77

15x = 30

x = 2

∠MON = 6(2) + 3 = 15

6 0
4 years ago
Any help is appreciated because I have a probe in a couple of hours
Anit [1.1K]
1+1/x^2 when multiplied by x^2 we get: (x^2+1)/x^2.

5 0
3 years ago
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