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alexira [117]
4 years ago
5

Help me on number problem 4 please

Mathematics
2 answers:
dlinn [17]4 years ago
8 0

Let J be the number of points Jaylen scored, and T be the number of points Trevor scored. We have two pieces of information, which are enough to determine the values of the unknowns, because there are two of them (you need as many equations as unknowns).

The first thing we're told is that they scored 485 together, so you have

J+T=485

Then we know that Jaylen scored 25 points less than Trevor, which means

J = T-25

Substitute this expression for J in the first equation to get

J+T=485 \iff (T-25)+T=485 \iff 2T=510 \iff T = 255

So, now that we know that Trevor scored 255 points, we can easily calculate Jaylen's score:

J = T-25 = 255-25 = 230

vaieri [72.5K]4 years ago
7 0
Jaylen score was 242.5 and Trevor score was 217.5
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The volume of the ball is 256 cm³

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7 0
4 years ago
X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4
AfilCa [17]
Given a solution y_1(x)=x^4, we can attempt to find another via reduction of order of the form y_2(x)=x^4v(x). This has derivatives

{y_2}'=4x^3v+x^4v'
{y_2}''=12x^2v+8x^3v'+x^4v''

Substituting into the ODE yields

x^2(x^4v''+8x^3v'+12x^2v)-7x(x^4v'+4x^3v)+16x^4v=0
x^6v''+(8x^5-7x^5)v'+(12x^4-28x^4+16x^4)v=0
x^6v''+x^5v'=0

Now letting u(x)=v'(x), so that u'(x)=v''(x), you end up with the ODE linear in u

x^6u'+x^5u=0

Assuming x\neq0 (which is reasonable, since x=0 is a singular point), you can divide through by x^5 and end up with

xu'+u=(xu)'=0

and integrating both sides with respect to x gives

xu=C_1\implies u=\dfrac{C_1}x

Back-substitute to solve for v:

v'=\dfrac{C_1}x\implies v=C_1\ln|x|+C_2

and again to solve for y:

y=x^4v\implies \dfrac y{x^4}=C_1\ln|x|+C_2
\implies y=C_1\underbrace{x^4\ln|x|}_{y_2}+C_2\underbrace{x^4}_{y_1}

Alternatively, you can solve this ODE from scratch by employing the Euler substitution (which works because this equation is of the Cauchy-Euler type), t=\ln x. You'll arrive at the same solution, but it doesn't hurt to know there's more than one way to solve this.
6 0
4 years ago
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