Hello from MrBillDoesMath!
Answer:
1/ 91.4
Discussion:
Evaluate 1/ ( 3x^3 + 5.2y) when x = 3, y = 2.
1/ (3 (3)^3 + 5.2(2)) =
1/ ( 3 * 27 + 10.4) =
1/ ( 81 + 10.4) =
1/ (91.4) =
.0109 (approx)
Thank you,
MrB
Answer:
T0 =0, T1=0
Step-by-step explanation:
Please kindly go through the attached files for a detailed explanation.
I arranged them from the first one to the last one.
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (5, -6)
Point (-3, 12)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance<em> d</em>
- Substitute in points [Distance Formula]:

- [√Radical] (Parenthesis) Subtract/Add:

- [√Radical] Evaluate Exponents:

- [√Radical] Add:

- [√Radical] Simplify:

Answer: ∠MON = 15°
Step-by-step explanation:
∠LON = ∠LOM + ∠MON
(9x + 44) + (6x+3) = 77
9x + 6x + 44 + 3 = 77
15x + 47 = 77
15x = 30
x = 2
∠MON = 6(2) + 3 = 15
1+1/x^2 when multiplied by x^2 we get: (x^2+1)/x^2.