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Sergeeva-Olga [200]
3 years ago
6

What are numbers 9 and 10

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

9) not factorable

10) not factorable

Step-by-step explanation:

that's probably why you were having a hard time (-_-)

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Please help me with part b of number 16.
natka813 [3]
You want to find the time (x) when the distance from desitnation is 0:

d = 0,

d(x) = 1375 - 110x
0 = 1375 - 110x
110x = 1375
x = 1375/110
<u>x = 12.5 hrs</u>
7 0
3 years ago
How many students got eight or more answers correct?
slamgirl [31]

Answer:

9

Step-by-step explanation:

You have to count the number of dots there are after the number 8. (This includes the dotes above 8.)

7 0
3 years ago
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The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What
Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that \mu = 64.4, \sigma = 2.91

Sample of 50 women

This means that n = 50, s = \frac{2.91}{\sqrt{50}}

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}

Z = 1.46

Z = 1.46 has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

8 0
3 years ago
Owen plots the numbers 4, –6, –8, and –3 on a horizontal number line. Which list shows the numbers in the order in which they wo
olga_2 [115]

Answer:-8, -6,-3, 4 is the correct answer

Step-by-step explanation:

7 0
4 years ago
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Estimate the product of -3.33 and 0.199 using the compatible numbers -3 and 0.2. Find the exact product of -3.33(0.199).
posledela

Answer:

-0.6

-0.66267

Step-by-step explanation:

Estimating the product :

Using compatible number :

-3 * 0.2

__ 0.2

* ___-3

______

_ - 0.6

______

-3 * 0.2 = 0.6

The exact product :

-3.33(0.199).

Using calculator :

-3.33(0.199) = - 0.66267

6 0
3 years ago
Read 2 more answers
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