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trapecia [35]
3 years ago
12

What are the answers

Mathematics
1 answer:
evablogger [386]3 years ago
5 0
1) 12 x^{11}
2) 14 a^{3}  b^{10}
3) c^{5}  d^{7}
4) 3^{5} = 243
5) 125 a^{18}  b^{31}
6) 2^{5} = 32
7) \frac{1}{ x^{8} }
8) \frac{ x^{2}  a^{3} }{  t^{7} }
9) \frac{2 x^{5} }{ y^{4} z^{3}  }
10) 1
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Evaluate the line integral c y3 ds,<br> c.x = t3, y = t, 0 ≤ t ≤ 3
Temka [501]
\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\int_{t=0}^{t=3}t^3\sqrt{1^2+(3t^2)^2}\,\mathrm dt=\int_0^3t^3\sqrt{1+9t^4}\,\mathrm dt

Take u=1+9t^4 so that \mathrm du=36t^3\,\mathrm dt. Then

\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\frac1{36}\int_{u=1}^{u=730}\sqrt u\,\mathrm du=\frac{730^{3/2}-1}{54}
7 0
3 years ago
Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.
Alborosie
Assume that the rule connecting height of the candle to time is a linear one.  If you do, then we have to find the equation of this line, and then use this equation to predict the height of the candle after 11 hours.

Two points on this line are (6,17.4) and (23, 7.2).  The slope is thus
         7.2-17.4           -6
m = ---------------  =  -----------  or   -3/5.
           23-6                 10

Find the equation of the line.  I'm going to use the slope-intercept formula:

y = mx + b  =>   7.2 = (-3/5)(23) + b.  Solving for b,   b = 21.

Now    we know that y = (-3/5)x + 21

Let x=11 to predict the height of the candle at that time.

y = (-3/5)(11) + 21 = 14.4 inches  (answer)
7 0
3 years ago
I don't know what to do in this problem.
RUDIKE [14]
If you see that the temperature rose in the next 4 hours and the temperture was taken at noon so the answer would be D there was no change in temperature
5 0
3 years ago
. The sandwich shop offers 8 different sandwiches. Jamey likes them all equally. He picks one randomly each day for lunch. Durin
Margarita [4]

Answer:

Step-by-step explanation:

From the given information:

A sandwich shop offers eight types of sandwiches, and Jamey likes all of them equally.

The probability that Jamey picks any one of them is 1/8

Suppose

X represents the number of times he chooses salami

Y represents the number of times he chooses falafel

Z represents the number of times he chooses veggie

Then  X+Y+Z ≤ 5 and;

5-X-Y-Z represents the no. of time he chooses the remaining

8 - 3 = 5 sandwiches

However, the objective is to determine the P[X=x,Y=y,Z=z] such that 0≤x,y,z≤5

So, since he chooses x no. of salami sandwiches with probability (1/8)x

and y number of falafel with probability (1/8)y

and for z (1/8)z

Therefore, the remaining sandwiches are chosen with probability \dfrac{5}{8} (5-x-y-z)

So. these x days, y days and z days can be arranged within five days in

= \dfrac{5!}{x!y!z!(5-x-y-z)!}

Thus;

P[X=x,Y=y,Z=z]=  \dfrac{5!}{x!y!z!(5-x-y-z)}  \times \dfrac{1}{8}x*\dfrac{1}{8}y* \dfrac{1}{8}z* \dfrac{5}{8}(5-x-y-z)

since 0 ≤ x, y, z ≤ 5 and x + y + z ≤ 5.

The distribution is said to be Multinomial distribution.

5 0
3 years ago
Which values represent the first two terms of the sequence a1=2 and an=-2(an-1)^2?
Mars2501 [29]
Hello,

a_{1}=2
a_{n+1}=-2*a_{n}^2

a_{1}=2
a_{2}=-2*2^{2}=-8
a_{3}=-2*(-8)^{2}=-2*64=-128


Answer C






3 0
2 years ago
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