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OleMash [197]
3 years ago
13

The management of urbine corporation is considering the purchase of a machine that would cost $340,000 would last for 4 years, a

nd would have no salvage value. the machine would reduce labor and other costs by $80,000 per year. the company requires a minimum pretax return of 9% on all investment projects. (ignore income taxes in this problem.) click here to view exhibit 13b-1 and exhibit 13b-2 to determine the appropriate discount factor(s) using tables. the net present value of the proposed project is closest to: (round discount factor(s) to 3 decimal places, intermediate and final answers to the nearest dollar amount.)
Business
1 answer:
attashe74 [19]3 years ago
3 0

The net present value of the proposed project is closest to -$80,822.

Since the project saves $80,000 in costs each year, we treat these savings income for the next 4 years. We then calculate the Present value Interest Factor of an annuity using the formula :

PVIF of an annuity = { [ 1 - [ (1+r)⁻ⁿ ] } ÷ r

PVIF of an annuity = { [ 1 - [ (1.09)⁻⁴ ] } ÷ 0.09

PVIF of an annuity = 3.240 (rounded to three decimals)

PV of the cost savings = (3.240*80000) = $2,59,178 (rounded to nearest $)

NPV = PV of cost savings - Value of investment

NPV = 2,59,178 - 3,40,000

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When countries sell off state-owned enterprises and privatize them, it usually results in a(n)A. continuing drain on future natu
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4 years ago
Read 2 more answers
A graphics reproduction firm has four units of equipment that are automatic but occasionally become inoperative because of the n
elena55 [62]

Answer:

(a) Average number of unit in line  = 0.256

(b) Average number of unit in operation= 3.209

(c) Average number of unit being service in operation = 0.535

Explanation:

Given Data:

Number of machine N = 4

Number of attendant (S) = 1

Service time (T)= 5 mins

Time required by the machine before servicing = 30 mins

Calculating the service factor (X) using the formula;

X = T/(T+U)

    = 5/(5+30)

    = 5/35

     = 0.1429

(a) Calculating the average number of unit in line (L) using the formula;

L = N* (1-F)

where, N = Number of unit

F = efficiency factor

L = average number of unit in line

Using the finite queuing table at X = 0.1429 and S = 1,

Efficiency factor = 0.936

Substituting, we have;

L = 4*(1-0.936)

   = 4* 0.064

   = 0.256

(c) Calculating the average number of unit being service in operation (H) using the formula;

H = N*F*X

   = 4 *0.936*0.1429

   = 0.535

(b) Calculating the average number of unit in operation using the formula;

Average number of unit in operation= Number of unit-down unit

But down unit = L+H

The formula becomes;

Average number of unit in operation= Number of unit-(L+H)

                                                             = 4 - (0.256+0.535)

                                                             = 4-0.791

                                                             = 3.209

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