Answer : The volume of 6M NaOH stock solution is, 16.7 mL
Explanation :
To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:
where,
are the molarity and volume of NaOH stock solution.
are the molarity and volume of NaOH.
We are given:
Putting values in above equation, we get:
Thus, the volume of 6M NaOH stock solution is, 16.7 mL
Answer:
168.0 g
Explanation:
First thing, write a balanced chemical equation:
n(H2SO4) = concentration * volume
= 1.0 M * 2.0 L
= 2.0 mol
According to the balanced equation, 1 mol of acid requires 2 mol of sodium bicarbonate. This means that 2 mol of acid requires 2 mol of sodium bicarbonate. What mass of sodium bicarbonate is this?
mass (NaHCO3) = number of moles * molar mass
= 2.0 mol * 84.0065 g/mol
= 168.0 g