At the boiling point, external pressure is equal to the vapor pressure of water. Therefore, the vapor pressure of water at an ecternal pressure of 404 kPa is equal to 404 kPa as well. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
2 L is the new volume
Explanation:
We can apply the Ideal Gases Law to solve the problem.
At STP, we kwow that 1 mol of gas occupy a volume of 22.4 L
Then, how many moles do we have in 1 L?
Let's do it by a rule of three:
(1L . 1 mol) / 22.4L = 0.0446 moles
These moles are at 1 atm and 273 K of temperature, so let's change our conditions.
P . V = n . R .T
1 atm . V = 0.0446 mol . 0.082 L.atm/mol K . 546 K
V = 2 L
If we pay attention, we can notice that, if we double temperature, we double the volume.
Answer : The correct option is, (A) 51.1%
Explanation :
Mass percent : It is defined as the mass of the given component present in the total mass of the compound.
Formula used :
First we have to calculate the mass of 
and 
.
Mass of = 18 g/mole
Mass of 
= 7 × 18 g/mole = 126 g/mole
Mass of = 246.47 g/mole
Now put all the given values in the above formula, we get the mass percent of in .
Therefore, the mass percent of in is, 51.1%
True
After the process of Ore processing, Enrichment, Fuel production and being passed through the reactor core the last remaining step is spent fuel disposal.
