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Margarita [4]
3 years ago
14

The conjugate acid of ch3nh2 is ________. the conjugate acid of ch3nh2 is ________. ch3nh2+ ch3nh2 ch3nh3+ ch3nh+ none of the ab

ove
Chemistry
1 answer:
Verizon [17]3 years ago
3 0
The conjugate acid of ch3nh2 is ch3nh3+<span>.
</span>For example methylamine in water chemical reaction: 
CH₃NH₂(aq)+ H₂O(l) ⇌ CH₃NH₃⁺(aq) + OH⁻(aq).
According to  Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺). Methylamine (CH₃NH₂) is Bronsted base and it can accept proton and become conjugate acid (CH₃NH₃⁺).
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If an atom has an electron in the n = 4 state with ml = 2, what are the possible values of l?
Pavel [41]

Answer:

The possible values of l are 2 and 3

Explanation:

Each electrons have four quantum numbers:

  • n: the principal quantum number, which value matches with the energy level of the electron.
  • l: the secondary quantum number, which value can be from 0 to n-1
  • m: the magnetic number, which value can be from -l to l
  • sp: the spin number which value can be -1/2 or +1/2

In this case, n=4 so the values of l are:

l=0, 1, 2, 3

Now, if:

  • l=0 the value of m is m=0
  • l=1 the values of m are m= -1, 0, 1
  • l=2 the values of m are m= -2, -1, 0, 1, 2
  • l=3 the values of m are m= -3, -2, -1, 0, 1, 2, 3

Being all that said, l can be either  equal to 2 or 3

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3 years ago
Which factor determine the reactivity of alkyl halide
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Answer:

This reactivity order reflects both the strength of the C–X bond, and the stability of X(–) as a leaving group, and leads to the general conclusion that alkyl iodides are the most reactive members of this functional class.

6 0
3 years ago
The value of Henry's law constant for oxygen in water at 242C is 1.66 x 1 ox M/torr. b. c. Calculate the solubility of oxygen in
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What is the conclusion of an experiment
Misha Larkins [42]
The conclusion includes a summary of the results, whether or not the hypothesis was supported, the significance of the study, and future research.
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Read 2 more answers
The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc
jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br_2(g

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}

Given: -\frac{d[HBr]}{dt}]=0.301

Putting in the values we get:

\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}

+\frac{1d[Br_2]}{dt}=0.151

Thus the rate of appearance of Br_2 is 0.151

8 0
3 years ago
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